当第一个进程在python3中完成时，如何终止并行进程？

Question

问题：当流程1完成时，如何停止流程2

更长的版本：我制作了一个脚本，可以多处理2个函数，我真的不知道如何在第一个进程完成后停止第二个进程

我的代码：

def printHelloWorld(): # So this takes 5.0053 seconds to completly run
    print("Hello World.")
    time.sleep(5)
    print("Hello World. (after 5 seconds)")


def printText(): # And this takes 10.0102 seconds to completly run
    print("Some text.")
    time.sleep(10)
    print("Some text. (after 10 seconds)")


if __name__ == "__main__": # I multiprocessed these 2 functions to reduce time. 
    # But what I actually want is to terminate process 2 when process 1 has finished.
    p1 = Process(target = printHelloWorld) 
    p2 = Process(target = printText)
    p1.start()
    p2.start()          
    p1.join()
    p2.join()

我尝试了一个while循环来检查何时p1.is_alive == False，然后我应该终止进程2，但它不起作用。我也搜索了答案，但没有找到符合我要求的答案

谢谢你的阅读/回答

让我澄清一些事情：如果我不能正确解释，我很抱歉，但我想问的是，既然不再需要，我如何检查哪一个已经完成了第一个过程并终止第二个过程

示例：如果我们不知道函数1和2的执行时间（两个函数都在并行进程中），该怎么办。因此，一旦第一个进程停止，我希望另一个进程停止。我该怎么做？我希望现在能清楚地描述这一点。再次为混乱感到抱歉

Answer 1

我建议你利用图书馆。它包装了Python的标准库线程和多处理对象。但是它很有可能取消正在运行的呼叫

import time
from concurrent.futures import wait, FIRST_COMPLETED
from pebble import ProcessPool

def printHelloWorld():  # So this takes 5.0053 seconds to completly run
    print("Hello World.")
    time.sleep(5)
    print("Hello World. (after 5 seconds)")


def printText():  # And this takes 10.0102 seconds to completly run
    print("Some text.")
    time.sleep(10)
    print("Some text. (after 10 seconds)")


if __name__ == "__main__":  # I multiprocessed these 2 functions to reduce time.
    with ProcessPool(max_workers=2) as pool:
        f1 = pool.schedule(printHelloWorld)
        f2 = pool.schedule(printText)
        done, not_done = wait((f1, f2), return_when=FIRST_COMPLETED)
        for f in not_done:
            f.cancel()

Answer 2

你试过Process.terminate吗

import time
from multiprocessing import Process


def printHelloWorld(): # So this takes 5.0053 seconds to completly run
    print("Hello World.")
    time.sleep(5)
    print("Hello World. (after 5 seconds)")


def printText(): # And this takes 10.0102 seconds to completly run
    print("Some text.")
    time.sleep(10)
    print("Some text. (after 10 seconds)")


if __name__ == "__main__": # I multiprocessed these 2 functions to reduce time.
    # But what I actually want is to terminate process 2 when process 1 has finished.
    p1 = Process(target = printHelloWorld)
    p2 = Process(target = printText)
    p1.start()
    p2.start()
    p1.join()
    p2.terminate()  # terminate process 2
    p2.join()