pythoninc用一个空格替换多个新行和一个新行的方法是什么？

Question

我有一个字符串：

"2\nOur\nstrategy drives \nsustainably higher profits and margins\n\nStrengthening our hubs is a critical foundation to maximize profitability\n\nDriving revenue improvements from all areas of business\n\nImproving efficiency and productivity \n\nGreater accountability and transparency\n"

输出应为：

"2 Our strategy drives sustainably higher profits and margins\nStrengthening our hubs is a critical foundation to maximize profitability\nDriving revenue improvements from all areas of business\nImproving efficiency and productivity \nGreater accountability and transparency "

Answer 1

创建映射字典：

dct = {'\n\n': '\n', '\n': ' '}

使用re.sub（这个regex的顺序很重要）：

re.sub(r'(\n\n|\n)', lambda x: dct[x.group()], s)

输出：

'2 Our strategy drives  sustainably higher profits and margins\nStrengthening our hubs is a critical foundation to maximize profitability\nDriving revenue improvements from all areas of business\nImproving efficiency and productivity \nGreater accountability and transparency '

解释一下这是怎么回事。Python的正则表达式模块不支持重叠匹配，因此当它匹配\n\n时，它也不会匹配\n，这允许您在一个步骤中完成两个替换。你知道吗

Answer 2

使用re.sub：

import re
s = "string\n\n\nwith\n\nmultiple\n\n\nnewlines"
# Replace all multiple newlines with one newline
new_string = re.sub(r'\n+', '\n', s)

Answer 3

一种脓性溶液：

'\n'.join(e.replace('\n', ' ') for e in s.split('\n\n'))

首先，拆分出现'\n\n'的字符串，然后用'\n'替换列表中每个元素中的' '，最后，用'\n'连接所有内容。你知道吗

另一种解决方案

我将使用一个临时辅助字符串，它允许我临时替换双新行，然后用空格替换单新行，然后用新行替换临时辅助字符串：

假设您的字符串是s：

s = "2\nOur\nstrategy drives \nsustainably higher profits and margins\n\nStrengthening our hubs is a critical foundation to maximize profitability\n\nDriving revenue improvements from all areas of business\n\nImproving efficiency and productivity \n\nGreater accountability and transparency\n"

temp = '-\t-'
s = s.replace('\n\n', temp).replace('\n', ' ').replace(temp, '\n')