Python:csv outpu中的数据不匹配

Question

假设我有两个csv输出，如下所示：

mark1 :

[['a', '', '', '', '', ''], ['b', '', '', '', '', ''], ['c', '', '', '', '', ''], ['d', '', '', '', '', ''], ['e', '', '', '', '', ''], ['f', '', '', '', '', ''], ['g', '', '', '', '', '']]

以及

mark2:

[['a', '10', '', '', '', ''], ['b', '', '', '', '', ''], ['c', '10', '', '', '', ''], ['d', '', '', '', '', ''], ['e', '7', '', '', '', ''], ['m', '9', '', '', '', ''], ['n', '', '', '', '', '']]

在这种情况下，在第一个csv输出中找不到m和n。 所以我写的代码是：

mark1[row][0] != mark2[row1][0]:

            print 'some marks are not the same - no match found'

上面的代码不起作用。你知道吗

有什么具体的办法解决这个问题吗？你知道吗

谢谢。你知道吗

Answer 1

我先说我投票支持@ThaneBrimhall的答案，但是为了展示各种方式（假设你只关心一个元素是否在另一个元素中，而不管其位置如何）：

# Get a set of unique first elements for each list
set1 = set([n[0] for n in mark1])
set2 = set([n[0] for n in mark2])

# Items in mark1 but not mark2
if set1.difference(set2):
  print 'some marks are not the same - no match found'

# Items in mark2 but not mark1
if set2.difference(set1):
  print 'some marks are not the same - no match found'

如果你想知道是什么导致了错误：

# Get a set of unique first elements for each list
set1 = set([n[0] for n in mark1])
set2 = set([n[0] for n in mark2])

# Items in mark1 but not mark2
set1_diffs = set1.difference(set2)
if set1_diffs:
  print 'Marks {0} in mark1 but not mark2'.format(list(set1_diffs))

# Items in mark2 but not mark1
set2_diffs = set2.difference(set1)
if set2_diffs:
  print 'Marks {0} in mark2 but not mark1'.format(list(set2_diffs))