价值观不会改变

Question

我已经有一段时间的问题了，我的一些价值观只是拒绝存储。这很可能是因为我在某个地方违反了一条规则，但在互联网上搜索了一段时间后，我找不到问题所在。你知道吗

代码：

#TO SET#

def min_count_set():
  stancount = int(input("How many standard miners do you wish to start with? "))
  if (stancount > 10000 or stancount < 0):
    print("\n Please enter a valid number to start with. \n \n")
    min_count_set()
  else:
    advcount= int(input("How many advanced miners do you wish to start with? "))
  if (advcount > 10000 or advcount < 0):
    print("\n Please enter a valid number to start with. \n \n")
    min_count_set()
  else:
    ultrcount = int(input("How many ultra miners do you wish to start with? "))
  if (ultrcount > 10000 or ultrcount < 0):
    print("\n Please enter a valid number to start with. \n \n")
    min_count_set()
  else:
    print("\n Returning you to the setup menu \n \n")
  set_mining_values()

#TO PRINT#
def view_mining_values():
  print("\n Printing all of the variables now.")
  print("\n Number of standard miners starting with: ")
  print(stancount)
  print("\n Number of advanced miners starting with: ")
  print(advcount)
  print("\n Number of ultra miners starting with: ")
  print(ultrcount)

我收到的错误是：

NameError: name 'stancount' is not defined

我以前试过给变量stancount一个数字，然后在输入中运行它，但是它只会在输入之前传递我给它的数字。你知道吗

Answer 1

试图打印时，stancount变量超出范围。你知道吗

您可以将它作为参数传递到print_mining_values()函数中，并以这种方式打印它

所以print_mining_values()会变成：

def view_mining_values(sCount, aCount, uCount):
    print("\n Printing all of the variables now.")
    print("\n Number of standard miners starting with: ")
    print(sCount)
    print("\n Number of advanced miners starting with: ") 
    print(aCount) 
    print("\n Number of ultra miners starting with: ")
    print(uCount)

你的min_count_set()函数会变成：

def min_count_set():
    stancount = int(input("How many standard miners do you wish to start with? "))
    if (stancount > 10000 or stancount < 0):
        print("\n Please enter a valid number to start with. \n \n")
        min_count_set()
    else:
        advcount= int(input("How many advanced miners do you wish to start with? "))
    if (advcount > 10000 or advcount < 0):
        print("\n Please enter a valid number to start with. \n \n")
        min_count_set()
    else:
        ultrcount = int(input("How many ultra miners do you wish to start with? "))
    if (ultrcount > 10000 or ultrcount < 0):
        print("\n Please enter a valid number to start with. \n \n")
        min_count_set()
    else:
        print("\n Returning you to the setup menu \n \n")
    set_mining_values(stancount, advcount, ultrcount)

注意变量现在被传递到打印函数中。你知道吗

Answer 2

可以将stancount声明为全局变量，如下所示：

def min_count_set():
    global stancount

Answer 3

您必须在函数外部声明变量，并在函数内部修改它们，因为变量在定义它们的地方是局部的，因为您在函数内部定义stancount，当您离开函数时，它基本上被“删除”：我推荐类似的方法

def min_count_set():
  stancount = int(input("How many standard miners do you wish to start with? "))
  #do stuff
  set_mining_values()
  return stancount


def view_mining_values(stancount):
  print("\n Printing all of the variables now.")
  print("\n Number of standard miners starting with: ")
  print(stancount)
  #do more stuff

stancount=min_count_set()

这将stancount设置为您在函数中设置的值，并允许您在以后打印它