擅长:python、mysql、java
<p>您必须在函数外部声明变量,并在函数内部修改它们,因为变量在定义它们的地方是局部的,因为您在函数内部定义<code>stancount</code>,当您离开函数时,它基本上被“删除”:我推荐类似的方法</p>
<pre><code>def min_count_set():
stancount = int(input("How many standard miners do you wish to start with? "))
#do stuff
set_mining_values()
return stancount
def view_mining_values(stancount):
print("\n Printing all of the variables now.")
print("\n Number of standard miners starting with: ")
print(stancount)
#do more stuff
stancount=min_count_set()
</code></pre>
<p>这将<code>stancount</code>设置为您在函数中设置的值,并允许您在以后打印它</p>