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<p>我有一个排序请求下面的例子。</p>
<p>我需要重新设置索引(),然后排序(),然后设置索引()还是有一种巧妙的方法?</p>
<pre><code>l = [[1,'A',99],[1,'B',102],[1,'C',105],[1,'D',97],[2,'A',19],[2,'B',14],[2,'C',10],[2,'D',17]]
df = pd.DataFrame(l,columns = ['idx1','idx2','col1'])
df.set_index(['idx1','idx2'],inplace=True)
# assume data has been received like this...
print df
col1
idx1 idx2
1 A 99
B 102
C 105
D 97
2 A 19
B 14
C 10
D 17
# I'd like to sort descending on col1, partitioning within index level = 'idx2'
col1
idx1 idx2
1 C 105
B 102
A 99
D 97
2 A 19
D 17
B 14
C 10
</code></pre>
<hr/>
<p>谢谢你的回答
注:我稍微更改了数据:</p>
<pre><code>l = [[1,'A',99],[1,'B',11],[1,'C',105],[1,'D',97],[2,'A',19],[2,'B',14],[2,'C',10],[2,'D',17]]
df = pd.DataFrame(l,columns = ['idx1','idx2','col1'])
df.set_index(['idx1','idx2'],inplace=True)
df = df.sort_index(by='col1', ascending=False)
</code></pre>
<p>但是输出是</p>
<pre><code>idx1 idx2
1 C 105
A 99
D 97
2 A 19
D 17
B 14
1 B 11
2 C 10
</code></pre>
<p>我本想是的</p>
<pre><code>idx1 idx2
1 C 105
A 99
D 97
B 11
2 A 19
D 17
B 14
C 10
</code></pre>