我怎么才能只打印出不为零的硬币？

Question

现在，我的代码会打印出“0角硬币”或“0便士”如果没有硬币，我需要知道如何制作它，这样如果某个硬币有0，那么就不会为该硬币打印任何内容。在

  #Asks user how much change they are trying to give, returns the coins to make that change

  coin = int(input("How much change are you tring to give (in cents)? "))


  while coin >= 25: 

      quarters = coin // 25
      coin = coin % 25

      if coin >= 10:
          dimes = coin // 10
          coin = coin % 10

      if coin >= 5:
          nickels = coin // 5
          coin = coin % 5

      pennies = coin // 1
      coin %= 1

      print ("You have ",quarters,"quarters", dimes, "dimes,",nickels,"nickels and ",pennies,"pennies.")

例如，如果更改为1/4和2个镍币，它将打印：（您有1/4、0个1角、2个镍币和0个便士）

我需要它来打印（你有1/4和2个镍币）

Answer 1

字符串连接这里是你的朋友！与其有一个非常大的打印声明，不如尝试这样的方法：

print_str = ''
if quarters > 0:
    print_str += 'You have ' + str(quarters) + ' quarters.'

然后，在最后，打印出你的指纹

请注意，您可能希望在字符串中有换行符。我建议你在这里阅读字符串：http://www.tutorialspoint.com/python/python_strings.htm

Answer 2

让我们将硬币检查到您当前的代码中，然后构建输出字符串。请注意，我们永远不会给多个镍币。在

# Asks user how much change they are trying to give, returns the coins to make that change

coin = int(input("How much change are you trying to give (in cents)? "))
change = ""

while coin >= 25:

    quarters = coin // 25
    coin = coin % 25
    if quarters > 0:
        change += str(quarters) + " quarters "

    if coin >= 10:
        dimes = coin // 10
        coin = coin % 10
        change += str(dimes) + " dimes "

    if coin >= 5:
        nickels = coin // 5
        coin = coin % 5
        change += str(nickels) + " nickel "

    pennies = coin // 1
    coin %= 1
    if pennies > 0:
        change += str(pennies) + " pennies "

    print (change)