Python代码输入验证字典

Question

我刚刚创建了一个python字典，它是可执行的。例如，如果有人在里程表读数中输入文本而不是数字，如何验证用户输入以给出异常错误？下面是代码。感谢你的反馈团队。在

Auto_details = {'Car brand': input('Car brand:'),
                'Car model': input('Car model:'),
                'Model Year': input('Model Year:'),
                'Starting odometer reading': int(input('Starting odometer reading:')),     
                'Ending odometer reading': int(input('Ending odometer reading:')),
                'Miles per gallon': int(input('Miles per gallon:')),
               }
print(Auto_details)
input ('Thank you. Please press Enter to exit')

Answer 1

你可以这样做：

def get_number(hint):
    while True:
        try:
            value = int(input(hint))
        except ValueError:
            print('Please input a number')
            continue

        if value<0:
            print('Please input a positive value')
            continue
        else:
            break
    return value

Auto_details =     {'Car brand': input('Car brand:'),
                   'Car model': input('Car model:'),
                   'Model Year': input('Model Year:'),
                   'Starting odometer reading': get_number('Starting odometer reading:'),     
                   'Ending odometer reading': get_number('Ending odometer reading:'),
                   'Miles per gallon': get_number('Miles per gallon:'),
               }
print(Auto_details)
input ('Thank you. Please press Enter to exit')

Answer 2

我没试过，但可能有用。在

Auto_details = {}
phrases=[
    ["Car brand",False], ["Car model",False],
    ["Model year",False],["Starting odometer reading",True],
    ["Ending odometer reading",True],["Miles per gallon",True]
]

for phrase in phrases:
    answer=input(phrase[0])
    if phrase[1]:
        while True:
            if answer.isdigit():
                answer=int(answer)
                break
            answer=input(phrase[0])
    Auto_details[phrase[0]]=answer