扫雷中的Python逻辑

Question

我正在写一个扫雷游戏。它一直很好，直到我遇到了一个问题，暴露多个瓷砖在一次点击。每当我点击某个东西时，它从不显示地雷（就像它应该显示的那样），只会一直向下，向左，向右。我做了它，所以它会打印出它的方向，它会认为向下是对的，等等。我从来没有遇到过左。这是我的代码：

from tkinter import *
from random import *

root = Tk()
root.resizable(0, 0)
root.title("Minesweeper")
frame = Frame(root)

Grid.rowconfigure(root, 0, weight=1)
Grid.columnconfigure(root, 0, weight=1)
frame.grid(row=0, column=0)

class Tiles:
    def __init__(self, frame, size, minecount):
        self.size = size
        self.frame = frame
        self.tiles = []
        self.minearray = []
        self.curmines = 0
        self.minecount = minecount

        for x in range(self.size):
            self.tiles.append([])
            self.minearray.append([])
            for y in range(self.size):
                self.minearray[x].append(0)
                self.tiles[x].append(Button())
                self.tiles[x][y] = Button(self.frame, text=' ', width=2, bd = 3, bg="#CDCDCD", command=lambda row=x, col=y: self.clicked(row, col))
                self.tiles[x][y].grid(row=x, column=y)

        self.setMines()

    def setMines(self):
        for i in range(self.minecount):
            self.minearray[randint(0, self.size - 1)][randint(0, self.size - 1)] = 1
            self.curmines += 1
        print(self.minearray)

    def clicked(self, x, y):
        if self.minearray[x][y] == 1:
            self.tiles[x][y]["text"] = '@'
        self.tiles[x][y]["relief"] = SUNKEN
        self.minearray[x][y] = 2
        if x < self.size - 1 and self.minearray[x+1][y] == 0:
            self.clicked(x+1, y)
            print('r')
            if y > 0 and self.minearray[x+1][y-1] == 0:
                self.clicked(x+1, y-1)
                print('rd')
            if y < self.size - 1 and self.minearray[x+1][y+1] == 0:
                self.clicked(x+1, y+1)
                print('ru')

        if x > 0 and self.tiles[x-1][y] == 0:
            self.clicked(x-1, y)
            print('l')
            if y > 0 and self.minearray[x-1][y-1] == 0:
                self.clicked(x-1, y-1)
                print('ld')
            if y < self.size - 1 and self.minearray[x-1][y+1] == 0:
                self.clicked(x-1, y+1)
                print('lu')

        if y < self.size - 1 and self.tiles[x][y + 1] == 0:
            self.clicked(x, y + 1)
            print('u')

        if y > 0 and self.tiles[x][y - 1] == 0:
            self.clicked(x, y - 1)
            print('d')

tiles = Tiles(frame, 10, 20)

root.mainloop()

逻辑在单击的函数中：

^{pr2}$

Answer 1

你似乎前后矛盾。在某些子句中，您检查self.minearray，而在其他子句中，您检查self.tiles。从初始化代码来看，它确实应该self.minearray，因为{}永远不会是{}。在