擅长:python、mysql、java
<p>这应该做到:</p>
<pre><code>df['Names'] = df['Names'].agg(lambda x: ','.join(map(str, x)))
df = df.groupby(by=['code1', 'code2'], as_index=False).agg('sum')
print(df)
code1 code2 Names
0 A k EUGENIO NETO,JUAN MATIAS SERAGOPIANSIMONE FANK...
1 B l EUGENIO LUPORINI NETO
</code></pre>