擅长:python、mysql、java
<p>这是我找到<code>t(m)</code>的解决方案</p>
<pre><code>n = [1,2,3]
m = int(input("number: ")) #eval is a big security risk!!!
while len(n) < m:
n.append((n[-3] * n[-2] - n[-1]))
print(n[m-1])
</code></pre>
<p>其中n[负数]是列表末尾的数字</p>
<p>结果:</p>
<pre><code>1, 2, 3, -1, 7, -10, 3, -73, 43, -262, -2877, -8389, 762163, 23372990, etc.
</code></pre>