我在获取所需输出时遇到问题(代码后显示) 我试过几种不同的方法,但似乎都不管用。 下面的代码正是我在尝试修复该问题时遗漏的代码
song_list = []
def get_songs(): # Just gets all songs ready and loaded for other things
global song_names
global song_amount
global song_list
############### Variables
songs_in_folder = list(os.listdir(input_folder)) # Grabs all files in folder Will add for actual .osz detection later on for this stage.
song_list.append(songs_in_folder) # Adds to song_list which is currently just used for testing else where.
# Checks if files are even in folder or not, does not check extentions, must fix in the future
if songs_in_folder >= 1:
song_amount = 1
else:
print("No Songs were found in the directory!")
time.sleep(2)
exit()
############### Code to clean up file names for users and stuff
for elem in songs_in_folder:
beatmap_name = elem[6:] # Cuts off the first 6 characters which are always 6 different numbers ex) 827212 nameless- Milk Crown On Sonnetica => nameless- Milk Crown On Sonnetica
songs_in_folder = string.strip(beatmap_name,'.osz') # Removes file extention '.osz' leaving just each songs name => nameless- Milk Crown On Sonnetica
######## Add song number and name together
song_list = ("[",song_amount,"]",songs_in_folder) # Fixes lists look without numbers or .osz extention. Easy to read this way.
song_amount = int(song_amount)
song_amount = song_amount + 1
song_list = str(song_list)
song_list = ''.join(song_list)
print(song_list)
get_songs()
问题:
输出结果为:('[', 18, ']', ' nameless - Milk Crown On Sonnetica')
而所需的输出/结果应该是:[song_number] Song name
请注意song_number
实际上只是song_amount
这是一个更直观的例子[18] nameless- Milk Crown On Sonnetica
如果有任何人有任何问题或意见,请评论这个问题,我会尽快回复你
字符串格式有问题。您似乎没有单独测试您的算法所包含的步骤,因此您不知道在哪里可以看到错误
以下是您的问题的可能解决方案:
主要的收获应该是,在编写一个长函数之前,测试每个可能的步骤
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