是否使用列表中的每个值筛选子集？

Question

我有一个大的数据集，我需要为它创建几个子集。我想获取列表中的每个字符串值，以过滤较大数据集中的一列，并另存为子集。因此，对于unique列表中的每个值，我需要过滤full_df并保存为子集

这需要某种函数、迭代或循环吗？感谢所有帮助解决此问题的人员

unique = ['aba', 'xyz', 'xgx', 'dssd', 'sdjh']

aba = full_df.loc[(full_df['filter'] == "aba")
xyz = full_df.loc[(full_df['filter'] == "xyz")
xgx = full_df.loc[(full_df['filter'] == "xgx")
dssd = full_df.loc[(full_df['filter'] == "dssd")
sdjh = full_df.loc[(full_df['filter'] == "sdjh")

Answer 1

这个想法似乎是正确的，只需在子集的值上循环

unique = ('aba', 'xyz', 'xgx', 'dssd', 'sdjh')
subset_dfs = {}

for unique_key in unique:
    subset_dfs[unique_key] = full_df.loc[full_df['filter'] == unique_key]

Answer 2

试着这样做：

d_df =  {}

unique = ['aba', 'xyz', 'xgx', 'dssd', 'sdjh']

for i in unique:
   d_df[i] = full_df.loc[full_df['filter'] == i]