点.py打印但停止打印

Question

好吧，我差不多做完这件事了。所以我被困在一个双循环，它不打印后，打印（赢），所以有些事情是不正确的，但我不知道是什么问题，但这里的代码。而且它没有为一个玩家储存笔记、提醒或点数。如果有人能帮我，我将不胜感激。你知道吗

    winnings = [] 
    for n in range(len(ratios)):
      winnings.append(pot*ratios[n])
    print(winnings) #STOPS HERE
    for winning in winnings[1:]:
      # loop over all but the first element in winnings
      winning = int(winning)
      for i, player in enumerate(players[1:]):
        # loop over all but the first player, adding indices
        notes.store("~lottery~", player, "The system has placed you %s in the lottery. The lottery awarded you %s P$" % (Point.ordinal(i), winning), time.time())
        alerts.append(player)
        point = Point.dPoint[player] + winning
        Point.dPoint[player] = point
    return True
  elif len(players) == 0:

Answer 1

如果winnings是长度为1的列表，则for o in range(1, len(winnings)):循环不会执行循环体，因为范围为空：

>>> list(range(1, 1))
[]

如果不想跳过第一个元素，请不要从1开始，而是从0开始循环：

>>> range(0, 1)
[0]

Python索引是基于0的。你知道吗

请注意，在Python中，通常直接循环列表，而不是先生成索引，然后生成索引。即使您仍然需要循环索引以及，您也可以使用enumerate()函数为您的循环添加索引：

winnings = [pot * ratio for ratio in ratios]
for winning in winnings[1:]:
    # loop over all but the first element in winnings
    winning = int(winning)
    for i, player in enumerate(players[1:]):
        # loop over all but the first player, adding indices
        notes.store("~lottery~", player, 
            "The system has placed you {} in the lottery. The lottery awarded "
            "you {} P$".format(Point.ordinal(i), winning), time.time())
        alerts.append(player)
        Point.dPoint[player] += winning

如果您需要将all赢款与all玩家配对，请使用zip()：

winnings = [pot * ratio for ratio in ratios]
for i, (winning, player) in enumerate(zip(winnings, players)):
    winning = int(winning)
    notes.store("~lottery~", player, 
        "The system has placed you {} in the lottery. The lottery awarded "
        "you {} P$".format(Point.ordinal(i), winning), time.time())
    alerts.append(player)
    Point.dPoint[player] += winning