如何比较不同对象的两个列表并返回匹配？

Question

我想拿这两张单子比较一下

list1 = [(Joe Black, married, happy),(Mili Cis, unmarried , happy),(Gary Oldman, married, unhappy)]
list2 = [Joe Black,Gary Oldman]

我想要新的清单：

list3 = [(Joe Black, married, happy),(Gary Oldman, married, unhappy)]

其中对对象的引用来自list1。你知道吗

Answer 1

试试这个：list3 = [x for x in list1 if x[0] in list2]

Answer 2

如果您想发布此代码：

list1 = [('Joe Black', 'married', 'happy'), ('Mili Cis', 'unmarried', 'happy'), ('Gary Oldman', 'married', 'unhappy')]
list2 = ['Joe Black', 'Gary Oldman']

那么这个列表就是你想要的：

list3 = [(name,status,desc) for (name,status,desc) in list1 if name in list2]

print(list3)

输出：

[('Joe Black', 'married', 'happy'), ('Gary Oldman', 'married', 'unhappy')]

Answer 3

常规方法：

list1 = [("Joe Black", "married", "happy"),("Mili Cis", "unmarried" , "happy"),("Gary Oldman", "married", "unhappy")]
list2 = ["Joe Black","Gary Oldman"]
a = []
for i in list1:
    if i[0] in list2:
        a.append(i)
print(a)

输出：

[('Joe Black', 'married', 'happy'), ('Gary Oldman', 'married', 'unhappy')]

使用列表理解：

list1 = [("Joe Black", "married", "happy"),("Mili Cis", "unmarried" , "happy"),("Gary Oldman", "married", "unhappy")]
list2 = ["Joe Black","Gary Oldman"]
a = [i for i in list1 if i[0] in list2]
print(a)

输出：

[('Joe Black', 'married', 'happy'), ('Gary Oldman', 'married', 'unhappy')]