Java：打印字符串中的唯一字符

Question

我正在编写一个程序，将打印字符串中的唯一字符（通过扫描仪输入）。我创建了一个方法，试图实现这一点，但我不断得到不重复的字符，而不是字符串特有的字符。我只想要独一无二的字母

这是我的代码：

import java.util.Scanner;
public class Sameness{
   public static void main (String[]args){
   Scanner kb = new Scanner (System.in); 
     String word = "";

     System.out.println("Enter a word: ");
     word = kb.nextLine();

     uniqueCharacters(word); 
}

    public static void uniqueCharacters(String test){
      String temp = "";
         for (int i = 0; i < test.length(); i++){
            if (temp.indexOf(test.charAt(i)) == - 1){
               temp = temp + test.charAt(i);
         }
      }

    System.out.println(temp + " ");

   }
}            

下面是上面代码的示例输出：

Enter a word: 
nreena
nrea 

预期的输出是：ra

Answer 1

应用接吻原则怎么样：

public static void uniqueCharacters(String test) {
    System.out.println(test.chars().distinct().mapToObj(c -> String.valueOf((char)c)).collect(Collectors.joining()));
}

Answer 2

这是一个面试问题。找出字符串的所有唯一字符。 以下是完整的解决方案。代码本身是不言自明的

public class Test12 {
    public static void main(String[] args) {
        String a = "ProtijayiGiniGina";

        allunique(a);
    }

    private static void allunique(String a) {
        int[] count = new int[256];// taking count of characters
        for (int i = 0; i < a.length(); i++) {
            char ch = a.charAt(i);
            count[ch]++;
        }

        for (int i = 0; i < a.length(); i++) {
            char chh = a.charAt(i);
            // character which has arrived only one time in the string will be printed out
            if (count[chh] == 1) {
                System.out.println("index => " + i + " and unique character => " + a.charAt(i));

            }
        }

    }// unique

}

在Python中：

def firstUniqChar(a):
    count = [0] *256
    for i in a: count[ord(i)] += 1
    element = ""

    for item in a:
        if (count[ord(item)] == 1):
            element = item;
            break;
    return element        


a = "GiniGinaProtijayi";
print(firstUniqChar(a)) # output is P

Answer 3

根据所需的输出，您必须替换一个最初已添加的字符，然后再添加一个重复的字符，因此：

public static void uniqueCharacters(String test){
    String temp = "";
    for (int i = 0; i < test.length(); i++){
        char current = test.charAt(i);
        if (temp.indexOf(current) < 0){
            temp = temp + current;
        } else {
            temp = temp.replace(String.valueOf(current), "");
        }
    }

    System.out.println(temp + " ");

}