如何使程序重新启动？

Question

重新启动程序时似乎出错，无法正确重新启动。它会询问你是否想再玩一次，然后询问球员的名字，告诉你目标，然后自己重新开始。你知道吗

import random, time

#Variables
die1 = 0
die2 = 0
goal = 0


 tries1 = 0

tries2 = 0
sum = 0
sum2 = 0
choice = "y"

while choice == "y":
#Asking for the player's names
    player1 = input("What is your name, player1?")
    player2 = input("What is your name, player2?")

#The "goal"
    goal = random.randrange(5) + 1
    print("The goal is:", goal)

#First while loop for the first die rolled by the first player
    while die1 != goal:
        die1 = random.randrange(5) + 1
        time.sleep(1)
        print(player1, "Your roll is:", die1)
        tries1 = tries1 + 1
        sum = sum + die1
        time.sleep(1.5)
        print("Your sum is:", sum)
#Second while loop for the second die rolled by the second player    
    while die2 != goal:
        die2 = random.randrange(5) + 1
        time.sleep(1)
        print(player2, "Your roll is:", die2)
        tries2 = tries2 + 1
        sum2 = sum2 + die2
        time.sleep(1.5)
        print("Your sum is:", sum2)

        time.sleep(2)

#The statement at the end of the game
        print("\n\n""Player", "\t\t", "Goal", "\t\t", "# of Rolls","\t\t", "Sum of Rolls", "\n", player1, "\t\t", goal, "\t\t", tries1,"\t\t\t", sum, "\n", player2, "\t\t", goal, "\t\t", tries2, "\t\t\t", sum2)
        choice = input("Would you like to play again?: (y) or (n)")
        goal = 0
        tries1 = 0
        tries2 = 0
        sum = 0
        sum2 = 0
        break

Answer 1

1. 代替你的分手声明，写上：

   if choice != 'y': break

如果用户键入了“y”，这将导致外部while循环返回到开头。否则您将跳出循环，脚本将退出。你知道吗

1. 在while循环中移动从die1到sum2的所有变量声明；否则它们将无法为重播进行初始化。你知道吗

Answer 2

这可能是因为在程序结束时，不管发生什么，你都会跳出主while循环。您应该用使用choice变量的if语句来包围它。另外，最后一条语句与while内联，当第二个玩家掷骰子时，它将在该循环中执行。为了解决这个问题，你需要减少缩进，这样就可以在游戏结束时执行了。而且tries1变量被缩进了一个空格，因此python可能也会抛出某种形式的语法错误。你知道吗