所以我创建了数据库,将一些数据存储到表中,并希望将其导入JSON格式,以便使用一些JS脚本将其可视化。但是当我试图把它写成JSON时
ValueError: No JSON object could be decoded
代码如下:
from PyBambooHR import PyBambooHR
import sqlalchemy
from sqlalchemy import Column, Integer, String
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import sessionmaker
import json
Base = declarative_base()
class EmployeeData(Base):
__tablename__ = 'employee_data'
id = Column(Integer, primary_key=True)
name = Column(String(120))
department = Column(String(120))
jobTitle = Column(String(120))
email = Column(String(120))
def __init__(self, name, department, jobTitle, email):
self.name = name
self.department = department
self.jobTitle = jobTitle
self.email = email
engine = sqlalchemy.create_engine('sqlite:///employee_db.db')
connection = engine.connect()
Base.metadata.create_all(engine)
bamboo = PyBambooHR(subdomain='domain', api_key='apikey')
session_factory = sessionmaker(engine)
session = session_factory()
employees = bamboo.get_employee_directory()
employees_list = [EmployeeData(name=item['displayName'], department=item['department'], jobTitle=item['jobTitle'], email=item['workEmail']) for item in employees]
avoid_duplicates = list(connection.execute('select * from employee_data'))
for i in employees_list:
if i.name not in [j[1] for j in avoid_duplicates]:
session.add(i)
session.commit()
session.close()
connection.close()
with open('employee_db.db', 'rb') as input_file:
content = json.load(input_file)
with open('employee_data.json', 'wb') as output_file:
json.dump(content,output_file, indent=1)
很明显:
你从哪里得到了这样一个巴洛克式的想法:sqlite数据库是json格式的?你知道吗
好的,这是工作代码,如果有人需要它来和BambooHR一起工作
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