我在Python中有一个函数,用来确定一个点是否在2d三角形中,如下所示:
def isInsideTriangle(P,p1,p2,p3): #is P inside triangle made by p1,p2,p3?
x,x1,x2,x3 = P[0],p1[0],p2[0],p3[0]
y,y1,y2,y3 = P[1],p1[1],p2[1],p3[1]
full = abs (x1 * (y2 - y3) + x2 * (y3 - y1) + x3 * (y1 - y2))
first = abs (x1 * (y2 - y) + x2 * (y - y1) + x * (y1 - y2))
second = abs (x1 * (y - y3) + x * (y3 - y1) + x3 * (y1 - y))
third = abs (x * (y2 - y3) + x2 * (y3 - y) + x3 * (y - y2))
return abs(first + second + third - full) < .0000000001
这是我的档案里的15分
^{pr2}$我的p1,p2和p3是三角形中的角坐标。它们来自这个文件:
TriangleXY
[193.0371, 0.1218346]
[193.0244, 0.1218346]
[186.0572, 0.4871899]
TriangleXY
[206.9799, 0.1218346]
[206.9756, 0.1218346]
[213.9428, 0.4871899]
TriangleXY
[193.0244, 0.1218346]
[193.0371, 0.1218346]
[200.0, 0.0]
TriangleXY
[206.9756, 0.1218346]
我想让我的脚本做的是,如果任何一个点在三角形(或三角形的边上)中,返回三角形p1、p2和p3的(3)特定坐标,以及其中的特定点p。它现在只适用于一个P和一组p1、p2和p3,我希望它适用于所有的点P和所有的三角形角p1、p2和p3。有人知道如何在我的脚本中相应地调整这个吗?我的P和p1、p2和p3由以下脚本调用:
# triangle coordinates p1 p2 p3
g = open("spheretop1.stl", "r")
m = open("TriangleXYcoordinates.gcode", "w")
searchlines = g.readlines()
file = ""
for i, line in enumerate(searchlines):
if "outer loop" in line:
p1 = map(float, searchlines[i+1].split()[1:3])
p2 = map(float, searchlines[i+2].split()[1:3])
p3 = map(float, searchlines[i+3].split()[1:3])
m.write("TriangleXY" + "\n" + str(p1) + "\n" + str(p2) + "\n" + str(p3) + "\n")
# Point coordinates P
import json
h = open("PointXYcoordinates.gcode", "r")
searchlines = h.readlines()
file = ""
for i, line in enumerate(searchlines):
if "PointXY" in line:
P = json.loads(searchlines[i+1].strip())
也许你想要这样的东西:
总的来说,你会有这样的东西:
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