pygame中的蛇游戏：身体生长函数

Question

我正在用pygame编写Snake，但是对于如何实现Snake不断增长的功能我还不太清楚。我做了一个列表（“lista_cobra”），包含头部坐标（大约30x30像素），并考虑从这个列表中创建另一个列表，包含头部的最后位置，不包括最后一个部分，因此绘制了一张身体蛇的图片（“corpito”也是30x30像素），从那里，每个点都累积起来。这个想法付诸实践时效果不太好，因为我认为身体的方式不能使蛇的特征运动。我的问题是如何在保持身体特征性运动的同时，从头部先前的坐标中生长出身体？在

#-*- coding: latin1 -*-

import pygame, sys, os, random, math, time
from pygame.locals import *

pygame.init()

##### Cores ######
preto = (0, 0, 0)
vermelho = (255, 0, 0)
##################

##################

dimensao = [800, 600]
tela = pygame.display.set_mode(dimensao)

######### Objetos ###########

gramado = pygame.image.load(os.path.join("images", "fundocobrinha.jpg"))
paredes = pygame.image.load(os.path.join("images", "paredes.png"))
comp = pygame.image.load(os.path.join("images", "comidacobra.png"))
comp = pygame.transform.scale(comp, (18, 20))
cabeca = pygame.image.load(os.path.join("images", "cabecadacobra.png"))
corpito = pygame.image.load(os.path.join("images", "corpodacobra.png"))
corpo = pygame.transform.rotate(cabeca, 0)
caminhodafonte = os.path.join("fonte", "lunchds.ttf")
fonte = pygame.font.Font(caminhodafonte, 22)
fonte_fim = pygame.font.Font(caminhodafonte, 25)

#############################

###### Distancia #########

def distancia(x, y, x2, y2):
    distancia = math.sqrt(((x2 - x) ** 2) + ((y2 - y) ** 2))
    return distancia

##########################

########### cobra #############

pontos = 0
vidas = 3
raio_cobra = 12
raio_corpo = 12
x = [130]
y = [130]

def cobrinha(): 
    global x, y, corpo, direcao, x_modificado, y_modificado

    tela.blit(corpo, (x[0] - raio_cobra, y[0] - raio_cobra))

    if direcao == "direita":
        corpo = pygame.transform.rotate(cabeca, 0)
        x_modificado = 3
        y_modificado = 0
    elif direcao == "esquerda":
        corpo = pygame.transform.rotate(cabeca, 180)
        x_modificado = -3
        y_modificado = 0
    elif direcao == "cima":
        corpo = pygame.transform.rotate(cabeca, 90)
        y_modificado = -3
        x_modificado = 0
    elif direcao == "baixo":
        corpo = pygame.transform.rotate(cabeca, 270)
        y_modificado = 3
        x_modificado = 0

    x[0] += x_modificado
    y[0] += y_modificado

################################

###### Comida da Cobra #########

raio_cCobra = 4
nova_comida = True
x2 = 0
y2 = 0

def comida():
    global x2, y2, comp, nova_comida
    if nova_comida:
        x2 = random.randint(47, 747)
        y2 = random.randint(56, 548)
        nova_comida = False
    tela.blit(comp, (x2 - raio_cCobra, y2 - raio_cCobra))

################################

########## Informações de status #############

def status_de_jogo():
    global pontos, fonte
    p = fonte.render("Pontos: " + str(pontos), True, preto)
    tela.blit(p, (45,37))
    v = fonte.render("Vidas :" + str(vidas), True, preto)
    tela.blit(v, (45,61))

###############################

######## mensagen de tela ######

def mensagem_de_tela():
    mensagem_de_texto = fonte_fim.render("Fim de Jogo, pressione C para jogar ou Q para sair.", True, vermelho)
    tela.blit(mensagem_de_texto,[55,200])

################################

######################################## Loop principal ###################################################

def loop_jogo():
    global x, y, x2, x2, vidas, pontos, distancia, corpo, raio_cCobra, raio_cobra, counter, nova_comida, lista_cobra,lista_corpo, direcao

    direcao = "direita" 

    lista_cobra = []

    clock = pygame.time.Clock()

    sair_do_jogo = False
    fim_de_jogo = False

    while not sair_do_jogo:

        while fim_de_jogo == True:
            mensagem_de_tela()
            pygame.display.update()
            for event in pygame.event.get():
                if event.type == pygame.KEYDOWN:
                    if event.key == pygame.K_q:
                        sair_do_jogo = True
                        fim_de_jogo = False
                    if event.key == pygame.K_c:
                        loop_jogo()

        #### Capturando todos os eventos durante a execução ####
        for event in pygame.event.get():
            if event.type == pygame.KEYDOWN:
                if event.key == pygame.K_RIGHT:
                    direcao = "direita"

                elif event.key == pygame.K_LEFT:
                    direcao = "esquerda"

                elif event.key == pygame.K_UP:
                    direcao = "cima"

                elif event.key == pygame.K_DOWN:
                    direcao = "baixo"

            if event.type == QUIT:
                sair_do_jogo = True

        ####### posição da cabeça da cobra ###########

        cabeca_cobra = []
        cabeca_cobra.append(x[0])
        cabeca_cobra.append(y[0])
        lista_cobra.append(cabeca_cobra)

        tela.blit(gramado, (0, 0))
        tela.blit(paredes, (0, 0))

        comida()
        cobrinha()
        status_de_jogo()

        clock.tick(60)

        fps = clock.get_fps()

        pygame.display.set_caption("Shazam Caraí II ## FPS: %.2f" %fps)

        ########## Se bater nas paredes ##################
        if (x[0] >= 751 or x[0] <= 44) or (y[0] >= 553 or y[0] <= 42):

            vidas -= 1
            x = 400
            y = 300

        ##################################################

        if distancia(int(x[0]), int(y[0]), x2, y2) < (raio_cobra + raio_cCobra):

            nova_comida = True
            pontos += 1

        if vidas == 0:

            fim_de_jogo = True
            mensagem_de_tela()

        pygame.display.flip()
###########################################################################################################

loop_jogo()

Answer 1

我看不懂你的消息来源，但我想试试看。在

蛇的身体由lista_cobra中的位置组成。将蛇的长度存储在变量len_cobra中。现在，当头部继续移动时，头部的新位置必须添加到lista_cobra的顶部：

lista_cobra.insert(0, head_cobra)

但现在这个名单必须再次缩短到眼镜蛇的长度

^{pr2}$

现在回到你的问题上：如何培育蛇？这很容易做到，每次特定事件发生时（通常在一些移动之后）增加一个len_cobra。剩下的已经处理好了。在