我是一个正在学习Python基础知识的学生。我了解函数的工作原理,但不知道如何从单个函数返回多个变量。我可以用复制+粘贴来达到同样的效果,但是老师不接受。我希望运行函数两次,我希望程序保存两个输出,但只需几秒钟。下面是正在讨论的程序,当你进入你的生日时,它将以秒、分、小时、天、周、月和年来显示你的年龄。在
#Age Finder Program
#This program will calculate a person's age
import datetime
#Get current dates
current_month = datetime.date.today().month
current_day = datetime.date.today().day
current_year = datetime.date.today().year
def age():
#Get info
name = input('What is your name?')
print('Nice to meet you, ', name,)
print('Enter the following information to calculate your approximate age!')
month_birth = int(input('Enter the numerical month in which you were born: '))
day_birth = int(input('Enter the numerical day in relation to the month of which you were born: '))
year_birth = int(input('Enter the year in which you were born : '))
#Determine number of seconds in a day, average month, and a year
numsecs_day = 24 * 60 * 60
numsecs_year = 365 * numsecs_day
avg_numsecs_year = ((4 * numsecs_year) + numsecs_day) // 4
avg_numsecs_month = avg_numsecs_year // 12
#Calculate approximate age in seconds
numsecs_1900_dob = ((year_birth - 1900) * avg_numsecs_year) + \
((month_birth - 1) * avg_numsecs_month) + \
(day_birth * numsecs_day)
numsecs_1900_today = ((current_year - 1900) * avg_numsecs_year) + \
((current_month - 1) * avg_numsecs_month) + \
(current_day * numsecs_day)
age_in_secs = numsecs_1900_today - numsecs_1900_dob
age_in_minutes = age_in_secs / 60
age_in_hours = age_in_minutes / 60
age_in_days = age_in_hours /24
age_in_weeks = age_in_days / 7
age_in_months = age_in_weeks / 4.35
age_in_years = age_in_months / 12
#Output
print('Well,',name,', you are approximately', age_in_secs, 'seconds old!')
print('Or', age_in_minutes, 'minutes old!')
print('Or', age_in_hours, 'hours old!')
print('Or', age_in_days, 'days old!')
print('Or', age_in_weeks, 'weeks old!')
print('Or', age_in_months, 'months old!')
print('Or', age_in_years, ' years old!')
#Extra
if age_in_years < 18:
print('Have fun in School!\n')
age()
在python中,可以用元组返回变量,如下所示:
然后像这样打开它们:
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