有没有一种方法可以通过使用不同的声明字符串变量的后缀号作为迭代器来求和？

Question

我不想手动求和每个声明的字符串变量

word1 = "How"
word2 = "do"
word3 = "you"
word4 = "like"
word5 = "Python"
word6 = "so"
word7 = "far?"
totalword=word1+" "+word2+" "+word3+" "+word4+" "+word5+" "+word6+" "+word7
print(totalword)

Answer 1

有一种方法，但不是那么像Python：

word1 = "How"
word2 = "do"
word3 = "you"
word4 = "like"
word5 = "Python"
word6 = "so"
word7 = "far?"

for i in range(7):
    totalword += globals().get('word' + i)

Answer 2

这并不理想，但应该是可行的

word1 = "How"
word2 = "do"
word3 = "you"
word4 = "like"
word5 = "Python"
word6 = "so"
word7 = "far?"

mask = "word"

final = " ".join([eval(mask+str(x)) for x in range(1,8)])
print(final)

Answer 3

您可以使用表中的变量尝试类似的操作

word1 = "How"
word2 = "do"
word3 = "you"
word4 = "like"
word5 = "Python"
word6 = "so"
word7 = "far?"
words = [word1,word2,word3,word4,word5,word6,word7]
totalword = ""
for _ in range(len(words)):
    totalword += words[_]+" "
print(totalword)