Python正则表达式在模式匹配之前查找单词

Question

我有一根绳子

text1="Information for Conformity of Production for OVC-HEV \n  \nCombined \nCO2 emission (g/km) MC02,CS,COP \n216.66 \nAFCO2,CS \n1.02 \n \n \n2.1.2.2.2. CO2 mass emission of OVC-HEVs in case of a charge-depleting Type 1 test \n"

我想使用regex进入模式(\n2.1.2.2.2.)之前的单词

预期产出：

Combined CO2 emission (g/km) MC02,CS,COP 216.66 AFCO2,CS 1.02 

我编写了一个正则表达式字符串，用于搜索2.1.2.2.2之后的单词 但在反向搜索时不确定

这就是我试过的

text1='\n \n \n \nInformation for Conformity of Production for OVC-HEV \n  \nCombined \nCO2 emission (g/km) MC02,CS,COP \n216.66 \nAFCO2,CS \n1.02 \n \n \n2.1.2.2.2. CO2 mass emission of OVC-HEVs in case of a charge-depleting Type 1 test \n \nTest 1 \n \nCO2 Mass Emission (g/km) \nCombined \nCalculated Value MCO2,CD \n17.27 \n'

m8A = re.search(r'\b(2.1.2.2.2. CO2 mass emission of OVC-HEVs).*((?:\n.*){7})', text1)

d8A = {}

if m8A:

    d8A[m8A.group(1).strip()] = m8A.group(2).replace('\n', '').strip()

print(d8A)

Answer 1

我建议使用

(?m)^(\S.*(?:\n\S.*)*)(?:\n[ \t]*){2,}2\.1\.2\.2\.2\.

见regex demo详细信息：

• (?m)-多行模式
• ^-行的开始
• (\S.*(?:\n\S.*)*)-第1组：一个非空白字符，然后是零个或多个除换行符以外的字符（尽可能多），然后是零个或多个换行符+一个非空白字符+行的其余部分
• (?:\n[ \t]*){2,}-两个或多个连续序列：换行符、零个或多个空格或制表符
• 2\.1\.2\.2\.2\.-一个2.1.2.2.2.字符串

见Python demo：

import re
text1="Information for Conformity of Production for OVC-HEV \n  \nCombined \nCO2 emission (g/km) MC02,CS,COP \n216.66 \nAFCO2,CS \n1.02 \n \n \n2.1.2.2.2. CO2 mass emission of OVC-HEVs in case of a charge-depleting Type 1 test \n"
rx = r"(?m)^(\S.*(?:\n\S.*)*)(?:\n[ \t]*){2,}2\.1\.2\.2\.2\."
m = re.search(rx, text1)
if m:
    print( m.group(1).strip() )

输出：

Combined 
CO2 emission (g/km) MC02,CS,COP 
216.66 
AFCO2,CS 
1.02