l = [[g(x) for x in sub] for sub in iter]
# converts to:
l = []
for sub in iter:
temp = []
for x in sub:
temp.append(g(x))
l.append(temp)
因此,在您的情况下,只需添加条件,列表comp就变成:
sep_class = [[x for x, t in zip(X_train, y_train)if t ==c] for c in np.unique(y_train)]
# converts to:
sep_class = []
for c in np.unique(y_train):
sub = []
for x, t in zip(X_train, y_train):
if t == c:
sub.append(x)
sep_class.append(sub)
现在它们完全一样了
将列表理解转换为常规循环的最常用方法如下:
当您在理解中创建嵌套列表时,这会变得有点复杂,但遵循相同的逻辑,现在
f(x)
是列表comp本身的翻译。因此,我们:因此,在您的情况下,只需添加条件,列表comp就变成:
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