我有一个pandas数据框架,我想将其转换为JSON格式,供我的源系统使用,这需要一个非常特定的JSON格式
我似乎无法使用简单的字典循环获得预期输出部分所示的确切格式
我是否可以将csv/pd.Dataframe转换为嵌套的JSON? 有专门为此构建的python包吗
输入数据帧:
#Create Input Dataframe
data = {
'col6':['A','A','A','B','B','B'],
'col7':[1, 1, 2, 1, 2, 2],
'col8':['A','A','A','B','B','B'],
'col10':['A','A','A','B','B','B'],
'col14':[1,1,1,1,1,2],
'col15':[1,2,1,1,1,1],
'col16':[9,10,26,9,12,4],
'col18':[1,1,2,1,2,3],
'col1':['xxxx','xxxx','xxxx','xxxx','xxxx','xxxx'],
'col2':[2.02011E+13,2.02011E+13,2.02011E+13,2.02011E+13,2.02011E+13,2.02011E+13],
'col3':['xxxx20201107023012','xxxx20201107023012','xxxx20201107023012','xxxx20201107023012','xxxx20201107023012','xxxx20201107023012'],
'col4':['yyyy','yyyy','yyyy','yyyy','yyyy','yyyy'],
'col5':[0,0,0,0,0,0],
'col9':['A','A','A','B','B','B'],
'col11':[0,0,0,0,0,0],
'col12':[0,0,0,0,0,0],
'col13':[0,0,0,0,0,0],
'col17':[51,63,47,59,53,56]
}
pd.DataFrame(data)
预期输出:
{
"header1": {
"col1": "xxxx"
"col2": "20201107023012"
"col3": "xxxx20201107023012"
"col4": "yyyy",
"col5": "0"
},
"header2":
{
"header3":
[
{
col6: A,
col7: 1,
header4:
[
{
col8: "A",
col9: 1,
col10: "A",
col11: 0,
col12: 0,
col13: 0,
"header5":
[
{
col14: "1",
col15: 1,
col16: 1,
col17: 51,
col18: 1
},
{
col14: "1",
col15: 1,
col16: 2,
col17: 63,
col18: 2
}
]
},
{
col8: "A",
col9: 1,
col10: "A",
col11: 0,
col12: 0,
col13: 0,
"header5":
[
{
col14: "1",
col15: 1,
col16: 1,
col17: 51,
col18: 1
},
{
col14: "1",
col15: 1,
col16: 2,
col17: 63,
col18: 2
}
]
}
]
}
]
}
}
也许这会让你开始。我不知道当前有什么python模块可以满足您的需求,但这是我启动它的基础。根据您提供的内容做出假设
由于每个连续嵌套都基于某些条件,因此需要循环过滤数据帧。根据数据帧的大小,使用groupby可能是比我这里介绍的更好的选择,但理论是一样的。此外,您还必须正确地创建键值对,这只是创建了对您正在构建的数据的支持
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