在连接错误之后，如何获取请求的URL？

Question

我最近一直在尝试制作一个程序，返回缩短的URL（如bit.ly和t.co URL）导致使用Python请求库的URL。我已经能够使用此方法轻松地处理URL：

reveal = requests.get(shortenedUrl, timeout=5)
fullUrl = reveal.url

但是，当缩短的URL指向一个不真实的URL（例如：http://thisurldoesnotexistyet.com/）时，上述方法按预期返回ConnectionError。ConnectionError返回以下内容： HTTPSConnectionPool(host='thisurldoesnotexistyet.com', port=443): Max retries exceeded with url: / (Caused by ConnectTimeoutError(<urllib3.connection.VerifiedHTTPSConnection object at 0x00000213DC97F588>, 'Connection to thisurldoesnotexistyet.com timed out. (connect timeout=5)'))

发生这种情况时，我尝试使用此方法获取重定向URL：

try:
    reveal = requests.get(shortenedUrl, timeout=5)
    fullUrl = reveal.url
except requests.exceptions.ConnectionError as error:
    fullUrl = "http://" + error.host

但是，该方法不起作用（AttributeError: 'ConnectTimeout' object has no attribute 'host'）。有没有办法从错误中获取缩短的URL重定向到的URL

Answer 1

您正在请求一个不存在的url。因此，您将获得一个超时

>>> requests.get('https://does-not-exist')
... (suppressed for clarity)
requests.packages.urllib3.exceptions.MaxRetryError: HTTPSConnectionPool(host='does-not-exist', port=443): Max retries exceeded with url: / (Caused by NewConnectionError('<requests.packages.urllib3.connection.VerifiedHTTPSConnection object at 0x7f6b6dba7210>: Failed to establish a new connection: [Errno -2] Name or service not known'))

主机是您传入的url。您可以捕获异常并查看您传入的相同url，但是您将url传递给了requests.get

>>> try:
...     requests.get('https://does-not-exist')
... except requests.exceptions.ConnectionError as error:
...     print(error.request.url)
...
https://does-not-exist/