通过.txt文件进行分析时出现问题

Question

好的，我正在编写一个脚本，它通过.txt文件进行解析，并根据在文件中找到的某些字符串，提出某些建议

假设我想通过parameters.txt文件进行解析，该文件如下所示：

ztta/roll_memory = 250000
shm = 5000

现在，我使用的代码是：

  a = 'ztta/roll_memory = 250000'
  b = 'shm = 5000'
  with open('parameter.txt', 'r') as myfile:
  data = myfile.read()
  if a in data: 
     print("the value of ztta/roll_memory is correct --> PASS")
  else:
     print("the value of ztta/roll memory is incorrect --> FAIL")
  if b in  data:
     print("the value of shm is correct --> PASS")
  else:
     print("the value of shm is incorrect --> FAIL")

这里的问题是，如果.txt文件中的某个参数的值如下所示：

ztta/roll_memory = 2500 (**instead of 250000**), the if statement would still be triggered.

谢谢

Answer 1

另一种放置if a in data的方法是：

if 'ztta/roll_memory = 250000' in 'ztta/roll_memory = 250000':

您可以看到，子字符串a包含在比较字符串中， 不管它后面有多少个零

另一种说法是：

if 'ab' in 'abc' # True
if 'ab' in 'abd' # True
if 'hello00' in 'hello00000' # True

---

另一方面，您的代码是不可伸缩的。您应该尝试以ints而不是字符串的形式读入参数。即

good_values = {'ztta/roll_memory': 250000, 'shm': 5000}
params = {}

with open('parameter.txt','r') as myfile:
    for line in myfile:
        line_array = [x.strip() for x in line.split('=')]
        params[line_array[0]] = int(line_array[-1])

for key in params:
    if params[key] == good_values[key]:
        print("the value of {0} is correct  > PASS".format(key))
    else:
        print("the value of {0} is incorrect  > FAIL".format(key))