java组织。冬眠例外ConstraintViolationException:无法执行JDBC批处理更新&ORA02289:序列不存在

Question

这是我的pojo课程

package com.sathya.entity;

public class Customer { private String customerId; private String customerName; private String location; public Customer() {} public Customer(String customerId) { this.customerId=customerId;
} public Customer(String customerId,String customerName,String location) { this.customerId=customerId; this.customerName=customerName; this.location=location; } public String getCustomerId() { return customerId; } public void setCustomerId(String customerId) { this.customerId = customerId; } public String getCustomerName() { return customerName; } public void setCustomerName(String customerName) { this.customerName = customerName; } public String getLocation() { return location; } public void setLocation(String location) { this.location = location; } public String toString() { return "Customer["+customerId+","+customerName+","+location+"]"; } }

而我的客户计划是

>         package com.sathya.test;
>     
>     
>     
>     import org.hibernate.Session;
>     import org.hibernate.SessionFactory;
>     import org.hibernate.Transaction;
>     import org.hibernate.cfg.Configuration;
>     
>     import com.sathya.entity.Customer;
>     
>     public class InsertCustomer {
>     
>       public static void main(String[] args) 
>       {
>           Configuration config=new Configuration();
>           config.configure("com/sathya/config/hibernate.cfg.xml");
>           SessionFactory factory=config.buildSessionFactory();
>           Session session=factory.openSession();
>           Customer cust=new Customer();
>           cust.setCustomerName("sathya");
>           cust.setLocation("Hyd");
>           Transaction tx=session.beginTransaction();
>           session.save(cust);
>           tx.commit();
>           session.close();
>           factory.close();
>       }
>     
>     }

*

在尝试执行程序时出现错误，如ORA-01400:无法将NULL插入（“系统”、“客户”、“客户ID”）

*

Answer 1

您应该手动或通过自动策略设置ID。你可以使用Oracle，也可以使用序列