由于NoClassDefFoundError，java XStream无法反序列化XML

Question

因此，我尝试使用XStream库将一个简单对象序列化为XML文件

这些导致以下异常，抱怨找不到类人员。我曾尝试向Person类添加XStream注释，但也没有成功

使用XStream库（反）序列化对象的正确方法是什么

Exception in thread "main" java.lang.NoClassDefFoundError: org/xmlpull/v1/XmlPullParserException
    at com.thoughtworks.xstream.XStream.<init>(XStream.java:350)
    at XMLTest.main(XMLTest.java:10)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:497)
    at com.intellij.rt.execution.application.AppMain.main(AppMain.java:140)
Caused by: java.lang.ClassNotFoundException: org.xmlpull.v1.XmlPullParserException
    at java.net.URLClassLoader.findClass(URLClassLoader.java:381)
    at java.lang.ClassLoader.loadClass(ClassLoader.java:424)
    at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:331)
    at java.lang.ClassLoader.loadClass(ClassLoader.java:357)
    ... 7 more

为了完整起见，我在下面添加了我的代码

import com.thoughtworks.xstream.XStream;

public class XMLTest {

    public static void main(String[] args) {

        Person john = new Person("John", "Doe", 1234);

        XStream xstream = new XStream();
        String xml = xstream.toXML(john);

        Person newJohn = (Person) xstream.fromXML(xml);

        System.out.println("Hi " + newJohn.getFirstname());
    }
}

及

public class Person {
    private String firstname;
    private String lastname;
    private int age;

    public Person(String firstname, String lastname, int age) {
        this.firstname = firstname;
        this.lastname = lastname;
        this.age = age;
    }

    public String getFirstname() {
        return firstname;
    }

    public void setFirstname(String firstname) {
        this.firstname = firstname;
    }

    public String getLastname() {
        return lastname;
    }

    public void setLastname(String lastname) {
        this.lastname = lastname;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }
}

Answer 1

使用

XStream xstream = new XStream(new StaxDriver());

相反

原因是如果你这么做

XStream xstream = new XStream(new StaxDriver());

然后需要xstream-[version]。jar，xpp3-[版本]。jar和xmlpull-[version]。jar在类路径中。“但是XStream xstream = new XStream(new StaxDriver());不需要从Java6开始的XPP3库

一个非常简单的解释和更多信息可以在repo-source中获得