java将oracle十六进制字符串转换为实际字符串值
我已经从Oracle Logminor中提取了数据,您需要将其转换为有用的sql。以下是数据
SQL_REDO from logminer:
insert into "UNKNOWN"."OBJ# 74587"("COL 1","COL 2","COL 3","COL 4","COL 5","COL 6","COL 7","COL 8","COL 9")
values (HEXTORAW('c12d'),HEXTORAW('c4032c362e'),HEXTORAW('c3042222'),HEXTORAW('c105'),HEXTORAW('c3394c44'),HEXTORAW('c108'),HEXTORAW('c108'),HEXTORAW('c109'),HEXTORAW('c10b'));
Required Value:
Insert Into Scott.Test_Table
Select 44,2435345,33333,4.1234,567567,6.766,7,8,10 From Dual;
So I need help with the conversion from the Hex value to the actual value, this is for all data types.
for example:
c12d = 44
c4032c362e = 2435345
etc
下面是我试图转换的java代码,但它并没有完全将十六进制转换为字符串
public class StringToHex{
public String convertStringToHex(String str){
char[] chars = str.toCharArray();
StringBuffer hex = new StringBuffer();
for(int i = 0; i < chars.length; i++){
hex.append(Integer.toHexString((int)chars[i]));
}
return hex.toString();
}
public String convertHexToString(String hex){
StringBuilder sb = new StringBuilder();
StringBuilder temp = new StringBuilder();
//49204c6f7665204a617661 split into two characters 49, 20, 4c...
for( int i=0; i<hex.length()-1; i+=2 ){
//grab the hex in pairs
String output = hex.substring(i, (i + 2));
//convert hex to decimal
int decimal = Integer.parseInt(output, 16);
//convert the decimal to character
sb.append((char)decimal);
temp.append(decimal);
}
System.out.println("Decimal : " + temp.toString());
return sb.toString();
}
public static void main(String[] args) {
StringToHex strToHex = new StringToHex();
System.out.println("\n***** Convert ASCII to Hex *****");
String str = "2435345";
System.out.println("Original input : " + str);
String hex = strToHex.convertStringToHex(str);
System.out.println("Hex : " + hex);
System.out.println("\n***** Convert Hex to ASCII *****");
System.out.println("Hex : " + hex);
System.out.println("ASCII : " + strToHex.convertHexToString(hex));
}
}
请建议我如何理解Oracle十六进制代码以将其转换为实际字符串。根据上面的代码,它不是根据我上面提到的字符串
# 1 楼答案
我不知道为什么要提取原始值,但这些是the Oracle number datatype的二进制表示,它与Java中的任何数据类型都不对应
通过使用UTL_原始包,您可以看到该值的来源:
如果要将
C12D
从Oracle数字转换为十进制表示,可以使用UTL_RAW.CAST_TO_NUMBER
或you can do it the hard way:对于第一个字节,第一
1
位表示它是一个正数。剩下1000001 = 65
,我们减去64得到1,所以指数是100^1对于第二个字节
00101101 = 45
,减去1得到44。所以最后的数字是0.44 x 100^1
,或44我不会再讨论小数点或负数了,你可以自己读
我觉得你应该用
UTL_RAW.CAST_TO_NUMBER
# 2 楼答案
我已经找到了解决方案,请查看此代码