json错误“不是JSONObject”：以字符串形式返回此格式的API。如何使用Java从中读取和创建对象？

Question

这是请求：https://api-pub.bitfinex.com/v2/candles/trade:1h:tBTCUSD/hist?limit=2 答案是：

[[1607630400000,18399,18415,18450.367075,18399,279.63699634], [1607626800000,18290.48824022,18399,18400,18255,190.53601166]]

在另一篇帖子中，有人告诉我这是一个Json。。。但当我尝试这个：

public static void main(String[] args) throws IOException {
    String url = "https://api-pub.bitfinex.com/v2/candles/trade:1h:tBTCUSD/hist?limit=2";
    try {
        URL urlObj = new URL(url);
    
        HttpURLConnection conexion2 = (HttpURLConnection) urlObj.openConnection();
        conexion2.setRequestProperty("Accept-Language", "UTF-8");
        conexion2.setRequestMethod("GET");
        conexion2.connect();
        InputStreamReader in2 = new InputStreamReader(conexion2.getInputStream());
        BufferedReader br2 = new BufferedReader(in2);
        String output;
        output = br2.readLine();
        JSONArray array = new JSONArray(output);

        for (int i = 0; i < array.length(); i++) {
            JSONObject object = array.getJSONObject(0);
        }
    } catch (Exception e) {
        e.printStackTrace();
    }
}

输出为：

org.json.JSONException: JSONArray[0] is not a JSONObject.

也许我不需要将这个字符串转换成Json？但如何将该字符串转换为数组或列表

谢谢

Answer 1

根据你的回答

[[1607630400000,18399,18415,18450.367075,18399,279.63699634], [1607626800000,18290.48824022,18399,18400,18255,190.53601166]]

jsonArray中没有json对象，而是有另一个json数组。下面是一个可以工作的代码片段。必须在外观中获取JSONArray，然后在内部数组中获取元素。这是我对你们努力实现的理解

String output = "[[1607630400000,18399,18415,18450.367075,18399,279.63699634], [1607626800000,18290.48824022,18399,18400,18255,190.53601166]]";
    JSONArray array = new JSONArray(output);
    for (int i = 0; i < array.length(); i++) {
        JSONArray arr = array.getJSONArray(i);
        for (int j = 0; j < arr.length(); j++) {
            if( arr.get(j) instanceof Double )
                System.out.println(arr.getDouble(j));
            else if( arr.get(j) instanceof Long )
                System.out.println(arr.getLong(j));
            else if( arr.get(j) instanceof String )
                System.out.println(arr.getString(j));
            else
                System.out.println(arr.get(j));
        }
    }