两个安卓设备之间的java udp通信：如何响应

Question

我正在开发一个应用程序，如果用户连接到同一个网络，它将允许用户彼此通信。 我有udp_服务器类和sendMessage客户端方法。 问题是当客户端向服务器发送消息（sendMessage方法）时，服务器正确地读取了消息，但当服务器发送回复时，会显示消息已发送的Toast-这意味着respone已发送，但客户端未接收到消息。尝试catc块也不要捕获任何异常

udp_服务器类：

private class MyDatagramReceiver extends Thread {
        private boolean bKeepRunning = true;
        private String lastMessage = "";

        public void run() {
            String message;
            byte[] lmessage = new byte[1024*512];
            final DatagramPacket packet = new DatagramPacket(lmessage, lmessage.length);
            try {
                final DatagramSocket socket = new DatagramSocket(11234);
                while(bKeepRunning) {
                    socket.receive(packet);
                    message = new String(lmessage, 0, packet.getLength());
                    lastMessage = message;
                    runOnUiThread(updateTextMessage);

                    byte[] response = "response".getBytes();
                    final DatagramPacket response_packet = new DatagramPacket(response,response.length,InetAddress.getByName("192.168.8.111"),11234);
                    socket.send(response_packet);
                    runOnUiThread(new Runnable() {
                        @Override
                        public void run() {                                Toast.makeText(getApplicationContext(),"sended",Toast.LENGTH_LONG).show();
                        }
                    });
                }
            } catch (final Throwable e) {                 
                e.printStackTrace();
            }
        }
        public void kill() {
            bKeepRunning = false;
        }
        public String getLastMessage() {
            return lastMessage;
        }
    }

    private Runnable updateTextMessage = new Runnable() {
        public void run() {
            Toast.makeText(getApplicationContext(),"recived",Toast.LENGTH_LONG).show();
            if (myDatagramReceiver == null) return;
                adapter.add(myDatagramReceiver.getLastMessage());
        }
    }

客户端发送消息方法：

 private void sendMessage(final String message) {
        Thread thread = new Thread(new Runnable() {

            String stringData;

            @Override
            public void run() {
                DatagramSocket ds = null;
                try {
                    ds = new DatagramSocket();                      
                    InetAddress serverAddr = InetAddress.getByName("192.168.8.188");
                    DatagramPacket dp;
                    dp = new DatagramPacket(message.getBytes(), message.length(), serverAddr, 11234);
                    ds.send(dp);
                    byte[] lMsg = new byte[1000];
                    dp = new DatagramPacket(lMsg, lMsg.length);
                    ds.receive(dp);
                    stringData = new String(lMsg, 0, dp.getLength());

                } catch (final IOException e) {
                    e.printStackTrace();                      
                } finally {
                    if (ds != null) {
                        ds.close();
                    }
                }
            }
        });
        thread.start();
    }

有人知道那里发生了什么吗

决议： 我将sendMessage方法中的recive部分代码放入while循环，如下所示：

boolean keepWaiting = true;
while(keepWaiting) {
    ds.receive(packet);
    stringData = new String(lMsg, 0, packet.getLength());
    runOnUiThread(respone); //there I analize response
    keepWaiting = false;
}