java使用StringUtils的substringBetween（）方法获取两个标记之间的文本

Question

我有一个输入，比如：

<address>
    <addressLine>280 Flinders Mall</addressLine>
    <geoCodeGranularity>PROPERTY</geoCodeGranularity>
</address>
<address type="office">
    <addressLine>IT Park</addressLine>
    <geoCodeGranularity>office Space</geoCodeGranularity>
</address>

我想捕获地址标签之间的所有内容

我试过：

File file = new File("test.html");
String testHtml = FileUtils.readFileToString(file); 
String title = StringUtils.substringBetween(testHtml, "<address>", "</address>");

这并不适用于所有情况，因为地址标记可能包含某些属性。请帮助如何获取此类字符串的文本

Answer 1

通常，您应该而不是使用regex解析HTML/XML内容。相反，使用XPath之类的解析器。鉴于您似乎无法使用解析器，我们可以使用模式匹配器尝试以下选项：

int count = 0;
String input = "<address>\n<addressLine>280 Flinders Mall</addressLine>\n    <geoCodeGranularity>PROPERTY</geoCodeGranularity>\n</address>\n<address type=\"office\">\n    <addressLine>IT Park</addressLine>\n    <geoCodeGranularity>office Space</geoCodeGranularity>\n</address>";
String pattern = "<address[^>]*>(.*?)</address>";
Pattern r = Pattern.compile(pattern, Pattern.DOTALL);
Matcher m = r.matcher(input);

while (m.find( )) {
    count += m.group(1).length();
    System.out.println("Found value: " + m.group(1) );
}

System.out.println("count = " + count);  

这会发现样本数据中两个<address>标记的计数为198

要使用BufferedReader进行此操作，您可能必须确保一次读入一个完整的<address>标记

Answer 2

while (scan.hasNextLine()) {

        parser = scan.nextLine();
        // System.out.println(parser);
        if (parser.equals("<adress>")) {
            parser = scan.nextLine();
            // System.out.println(parser);
            int startPosition = parser.indexOf("<adressLine>") + "<adressLine>".length();
            int endPosition = parser.indexOf("</adressLine>", startPosition);
            idNumber = parser.substring(startPosition, endPosition);
            parser = scan.nextLine();

            int startPosition1 = parser.indexOf("<geoCodeGranularity>") + "<geoCodeGranularity>".length();
            int endPosition1 = parser.indexOf("</geoCodeGranularity>", startPosition1);
            time = parser.substring(startPosition1, endPosition1);
            parser = scan.nextLine();

。。。。。。 算法一定是这样的。如果你看了文件

Answer 3

您可以将文件转换为字符串，并可以确定所需子字符串的开始和结束索引，如下所示：

import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;

public class Address {

    public static void main(String[] args) throws IOException {

        // Complete File Path
        File dir =
            new File("\\..\\..\\Test.html");

        // Convert File Data As String
        String data =
            new String(
                Files.readAllBytes(Paths
                    .get(dir
                        .getAbsolutePath())));

        // For Loop to get all the <address> tags in the file.
        for (int index = data.indexOf("<address"); index >= 0;) {

            // Start Index
            int startIndex = data.indexOf(">", index + 1);
            ++startIndex;

            // End Index
            int indexOfEnd = data.indexOf("</address>", startIndex + 1);

            String attributesString = data.substring(startIndex, indexOfEnd);
            // Replace below line with desired logic with calling trim() on the String attributesString
            System.out.println(attributesString);

            // Next Address will be after the end of first address
            index = data.indexOf("<address", indexOfEnd + 1);
        }
    }
}