在Java中，如果响应时间超过n秒，api是否重新运行http post请求？

Question

我正在用Java调用RESTAPI，但有时响应中会偶尔出现延迟。因此，我想以某种方式检查响应是否花费了太长的时间（例如2秒或3秒），然后重新启动/重新运行http post请求，因为我不需要一个在等待响应时“卡住”的请求，而该响应可能会在很久很久以后出现

这是我到目前为止的一段代码：

private final CloseableHttpClient client;
HttpResponse response;
List<NameValuePair> parameters;
HttpPost post;

public String getRoleData(int roleid) {
    this.post = new HttpPost(this.createUrl("role/eventdata"));
    this.post.setHeader("apikey", this.apikey);
    this.parameters = new ArrayList<>();
    this.parameters.add(new BasicNameValuePair("roleid", String.valueOf(roleid)));
    try {
        post.setEntity(new UrlEncodedFormEntity(this.parameters));
        this.response = client.execute(post);
        String JsonResponse = EntityUtils.toString(this.response.getEntity(), StandardCharsets.UTF_8);
        return JsonResponse;
    } catch (UnsupportedEncodingException ex) {
        System.out.println("API Unsupported instruction entry");
    } catch (IOException ex) {
        System.out.println("API IO issue");
    }
    return "Empty response";
}

Answer 1

import java.io.IOException;
import java.io.UnsupportedEncodingException;
import java.nio.charset.StandardCharsets;
import java.util.ArrayList;
import java.util.List;

import org.apache.commons.httpclient.NameValuePair;
import org.apache.http.HttpResponse;
import org.apache.http.client.config.RequestConfig;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.CloseableHttpClient;
import org.apache.http.impl.client.HttpClientBuilder;
import org.apache.http.util.EntityUtils;

public class Test {

    public static void main(String[] args) {
        int timeoutInMillis = 10;
        RequestConfig config = RequestConfig.custom().
              setConnectTimeout(timeoutInMillis).
              setConnectionRequestTimeout(timeoutInMillis).
              setSocketTimeout(timeoutInMillis).build();
        final CloseableHttpClient client = HttpClientBuilder.create()
                  .setDefaultRequestConfig(config).build();
        HttpPost post = new HttpPost("https://reqres.in/api/api/users");
        //this.post.setHeader("apikey", this.apikey);
        List<NameValuePair> parameters = new ArrayList<NameValuePair>();
        parameters.add(new NameValuePair("name", "test1"));
        parameters.add(new NameValuePair("job", "job1"));
        try {
            //post.setEntity(new UrlEncodedFormEntity(this.parameters));
            HttpResponse response = client.execute(post);
            String jsonResponse = EntityUtils.toString(response.getEntity(), StandardCharsets.UTF_8);
            System.out.println(jsonResponse);
        } catch (UnsupportedEncodingException ex) {
            System.out.println("API Unsupported instruction entry");
        } catch (IOException ex) {
            System.out.println("IO issue" + ex.getCause().getClass());
        }
    }
}

它应该与上面类似。检查RequestConfig部件&；异常处理部分。您可以在错误处理&；再试一次。我们正在为http客户端设置超时值。你可以浏览一些java文档来了解更多细节

顺便说一下，您使用的是POST方法，根据定义，它不是幂等的。因此，在再次运行相同的请求时，需要小心。服务器可能已经在您获得超时后处理了