java将字符串拆分为子数组

Question

我有一个字符串，比如：

OG=ACC-0000000009| AMBORFFA KIRI|P.O.BOX 1FAF6GPO,GPO,FG/FFERER      OB=XXXX-XXCC|ABC|14332 X HWay|Vica |MNSJD      IS=BIC-dfsgdf|asas nduf|142 ERRET ERT RET|ERTERT Island|ERTERT     BF=ACC-0000013417711DD028|534 DFG ION|ONE DALLAERRS CENTER RR N.|     ERTERT, SUITE 1300, DRRALLAS,|Pb, 75201/ PBB      DT=GREAT CHART|0000FGHFGGL028434  

在OG、OB、IS等值之间没有分隔符。我希望根据“=”来拆分数组，以便OG、OB。。。字段包含在结果拆分中。我需要进一步处理子文件的这些字段

Answer 1

正则表达式可能是解决方案之一。但如果可以的话，我建议使用分隔符

这是我的解决方案，但我不确定它是否在所有情况下都有效：

public static void main(String[] args){

    String text = "OG=ACC-0000000009| AMBORFFA KIRI|P.O.BOX 1FAF6GPO,GPO,FG/FFERER      OB=XXXX-XXCC|ABC|14332 X HWay|Vica |MNSJD      IS=BIC-dfsgdf|asas nduf|142 ERRET ERT RET|ERTERT Island|ERTERT     BF=ACC-0000013417711DD028|534 DFG ION|ONE DALLAERRS CENTER RR N.|     ERTERT, SUITE 1300, DRRALLAS,|Pb, 75201/ PBB      DT=GREAT CHART|0000FGHFGGL028434";

    //Regex for field
    String regexField = "(?<field>[A-Z]+)(:?[=])";

    Pattern pattern = Pattern.compile(regexField);
    Matcher matcher = pattern.matcher(text);

    //extract fields names
    List<String> fields = new ArrayList<>();
    while(matcher.find()){
        fields.add(matcher.group("field"));
    }

    //extract values using split and regex for fields
    List<String> values = Arrays.stream(text.split(regexField))
                                .map(String::trim)
                                .filter(e -> !e.isEmpty())
                                .collect(Collectors.toList());

    //group fields and values
    Map<String, String> data = new HashMap<>();
    if(fields.size() == values.size()){

        for(int i = 0; i < fields.size(); i++){
            data.put(fields.get(i), values.get(i));
        }

    }else{

        System.out.println("Size are different. Something is not good.");

    }

    data.forEach((k, v) -> System.out.println(k + " -> " + v));

}

Answer 2

下面是一个Scala regex解决方案：

val data = "OG=ACC-0000000009| AMBORFFA KIRI|P.O.BOX 1FAF6GPO,GPO,FG/FFERER..."

data.split("""(?=\w\w=)""")

这使用了一种前瞻模式，在后面跟两个单词字符和一个=符号的点拆分数据

Answer 3

像这样的？（Scala代码）

val str =
  "OG=ACC-0000000009| AMBORFFA KIRI|P.O.BOX 1FAF6GPO,GPO,FG/FFERER      OB=XXXX-XXCC|ABC|14332 X HWay|Vica |MNSJD      IS=BIC-dfsgdf|asas nduf|142 ERRET ERT RET|ERTERT Island|ERTERT     BF=ACC-0000013417711DD028|534 DFG ION|ONE DALLAERRS CENTER RR N.|     ERTERT, SUITE 1300, DRRALLAS,|Pb, 75201/ PBB      DT=GREAT CHART|0000FGHFGGL028434  "

str.split("(?=\\S\\S=)")
   .foldLeft(Map.empty[String,Array[String]]){
     case (m,s) => m+(s.take(2) -> s.drop(3).split("\\|"))
   }
//res0: Map[String,Array[String]] = 
// HashMap(OG -> Array(ACC-0000000009, " AMBORFFA KIRI", "P.O.BOX 1FAF6GPO,GPO,FG/FFERER      ")
//       , OB -> Array(XXXX-XXCC, ABC, 14332 X HWay, "Vica ", "MNSJD      ")
//       , DT -> Array(GREAT CHART, "0000FGHFGGL028434  ")
//       , IS -> Array(BIC-dfsgdf, asas nduf, 142 ERRET ERT RET, ERTERT Island, "ERTERT     ")
//       , BF -> Array(ACC-0000013417711DD028, 534 DFG ION, ONE DALLAERRS CENTER RR N., "     ERTERT, SUITE 1300, DRRALLAS,", "Pb, 75201/ PBB      "))

---

更新：根据评论添加新要求

val str =
  "OG=ACC-0000000009| AMBORFFA KIRI|P.O.BOX 1FAF6GPO,GPO,FG/FFERER Transaction Amount= 1223|546SD|376KL OB=XXXX-XXCC|ABC|14332 X HWay|Vica |MNSJD      IS=BIC-dfsgdf|asas nduf|142 ERRET ERT RET|ERTERT Island|ERTERT     BF=ACC-0000013417711DD028|534 DFG ION|ONE DALLAERRS CENTER RR N.|     ERTERT, SUITE 1300, DRRALLAS,|Pb, 75201/ PBB      DT=GREAT CHART|0000FGHFGGL028434  "

str.split(raw"\b(?=Transaction Amount=|\S\S=)")
   .foldLeft(Map.empty[String,Array[String]]){
     case (m,s) => val (k,v) = s.splitAt(s.indexOf("="))
                   m + (k -> v.tail.split("\\|"))
   }
//HashMap(OG -> Array(ACC-0000000009, " AMBORFFA KIRI", "P.O.BOX 1FAF6GPO,GPO,FG/FFERER ")
//      , OB -> Array(XXXX-XXCC, ABC, 14332 X HWay, "Vica ", "MNSJD      ")
//      , Transaction Amount -> Array(" 1223", 546SD, "376KL ")
//      , DT -> Array(GREAT CHART, "0000FGHFGGL028434  ")
//      , IS -> Array(BIC-dfsgdf, asas nduf, 142 ERRET ERT RET, ERTERT Island, "ERTERT     ")
//      , BF -> Array(ACC-0000013417711DD028, 534 DFG ION, ONE DALLAERRS CENTER RR N., "     ERTERT, SUITE 1300, DRRALLAS,", "Pb, 75201/ PBB      "))

Answer 4

 String OG = "ACC-0000000009| AMBORFFA KIRI|P.O.BOX 1FAF6GPO,GPO,FG/FFERER ";
    String[] split = OG.split(",");//以逗号为分隔符转换为字符串数组
    for (int i = 0; i < split.length; i++) {//遍历数组
        System.out.println(split[i]);