java如何通过单击通知转到活动？

Question

我正在开发一个向用户显示通知和通知声音的应用程序。用户可以通过“设置”活动上的两个开关按钮选择是否要查看它们。我想在用户单击通知时打开活动访问者。我写了下面的代码，但这没有发生，我应该写什么来代替

import 安卓.annotation.SuppressLint;
import 安卓.annotation.TargetApi;
import 安卓.app.Notification;
import 安卓.app.NotificationChannel;
import 安卓.app.NotificationManager;
import 安卓.app.PendingIntent;
import 安卓.content.Context;
import 安卓.content.Intent;
import 安卓.graphics.Color;
import 安卓.os.Build;
import 安卓.os.Bundle;
import 安卓.support.v4.app.NotificationCompat;
import 安卓.support.v4.app.NotificationManagerCompat;
import 安卓.support.v7.app.AppCompatActivity;
import 安卓.view.View;
import 安卓.widget.CompoundButton;
import 安卓.widget.Switch;

import java.util.Set;

import 安卓x.annotation.RequiresApi;

import static 安卓.app.PendingIntent.getActivity;
import static 安卓.content.Context.NOTIFICATION_SERVICE;
import static com.example.myevents.R.drawable.notification;


public class Settings extends AppCompatActivity {
    Switch simpleswitch1;
    Switch simpleswitch2;
    private Notification notification;
    NotificationManager manager;
    Notification myNotication;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_settings);


        simpleswitch1 = (Switch) findViewById(R.id.simpleswitch1);
        simpleswitch2 = (Switch) findViewById(R.id.simpleswitch2);
        simpleswitch1.setChecked(false);
        simpleswitch2.setChecked(false);
        simpleswitch1.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
            @TargetApi(Build.VERSION_CODES.O)
            @Override
            public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
                if (isChecked){{
                    int notifyID = 1;
                    String CHANNEL_ID = "my_channel_01";// The id of the channel.
                    CharSequence name = "channel 1";// The user-visible name of the channel.
                    int importance = NotificationManager.IMPORTANCE_HIGH;
                    NotificationChannel mChannel = new NotificationChannel(CHANNEL_ID, name, importance);

                    Intent intent = new Intent(Settings.this, Visitor.class);
                    intent.putExtra("yourpackage.notifyId", notifyID);
                    PendingIntent pIntent = PendingIntent.getActivity(Settings.this, 0, intent,
                            PendingIntent.FLAG_UPDATE_CURRENT);


// Create a notification and set the notification channel.
                    Notification notification =
                            new NotificationCompat.Builder(Settings.this)
                                    .setSmallIcon(R.drawable.notification)
                                    .setContentTitle("TITLE")
                                    .setContentText("TEXT")
                                    .setChannelId(CHANNEL_ID).build();



                    NotificationManager mNotificationManager =
                            (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
                    mNotificationManager.createNotificationChannel(mChannel);

// Issue the notification.
                    mNotificationManager.notify(notifyID , notification);



                }

Answer 1

正如Android文档中所述，您需要设置当用户点击构建器上的通知时将触发的意图：

NotificationCompat.Builder(Settings.this)
     .setSmallIcon(R.drawable.notification)
     .setContentTitle("My Events")
     .setContentText("Νέα εκδήλωση κοντά σας!")
     .setContentIntent(pIntent)
     .setChannelId(CHANNEL_ID).build();

见：https://developer.android.com/training/notify-user/build-notification#click