在java中用猜测的字母替换破折号

Question

这里是一个真正的javascript初学者，创建一个刽子手游戏。我很难向用户展示正确的猜测。 据我所知，我只是用破折号来掩盖这个秘密的单词，所以当猜对了一个正确的字母时，我试图让它暴露出来。 我想我需要在某个地方使用charAt，但老实说，我就是想不出来

我的代码仍然是非常基本的，我没有做太多的其他事情，因为如果你看不到猜测，那么写下游戏的其余部分就没有多大意义，但这是我到目前为止的代码。。。请记住，这仍然是一个非常未完成的项目

 package hangmangame;

import java.util.Arrays;
import java.util.Random;
import java.util.Scanner;

/**
*
* @author Matt
 */
public class HangmanGame {


/**
 * @param args the command line arguments
 */
public static void main(String[] args) 
{
    char letter = 0; //declares and initailise letter
    String marks = ""; //declares and initailise string for dashes
    String [] words = { "gluttony", "lust", "greed", "pride", "despair", "wrath", "vainglory", "rhythm", "delicious", "better", "jacuzzi" , "ironman", "captainamerica", "thor", "hulk", "spiderman", "antman", "batman"}; //declares and initailise array of words to guess
    String word = words[(int) (Math.random() * words.length)]; //chooses random word from the word array
    for (int i=1;i<=word.length(); i++) // for method for displaying the correct word as dashes
    {
        marks += "-"; //dashes to represent the correct word.
    }



        System.out.println("lets play hangman, your word is " + marks + "\n" + "enter a letter to guess the word");
        Scanner input = new Scanner(System.in);
        letter = input.next(".").charAt(0); //assign inputted letter to letter variable

     if ((word).contains(""+letter)) //if statement to excute if guessed letter is in word

         // i imagine this is where i put some sort of code to show that guessed letter?

         System.out.println("You guessed a letter!" + marks); //display for correct letter

Answer 1

我认为，如果您将单词和标记存储为如下字符数组，这一切都会容易得多：

char letter = 0; //declares and initailise letter
String [] words = { "gluttony", "lust", "greed", "pride", "despair", "wrath", "vainglory", "rhythm", "delicious", "better", "jacuzzi" , "ironman", "captainamerica", "thor", "hulk", "spiderman", "antman", "batman"}; //declares and initailise array of words to guess
String word = words[(int) (Math.random() * words.length)]; //chooses random word from the word array
char[] chosenWord = new char[word.length()];
char[] marks = new char[word.length];
for (int i=0;i< word.length(); i++) // for method for displaying the correct word as dashes
{
    chosenWord[i] = word.charAt(i);
    marks[i] = '-';
}



    System.out.println("lets play hangman, your word is " + new String(marks) + "\n" + "enter a letter to guess the word");
    Scanner input = new Scanner(System.in);
    letter = input.next(".").charAt(0); //assign inputted letter to letter variable

 if ((word).contains(""+letter)){ //if statement to excute if guessed letter is in word
      for(int i =0; i < chosenWord.length; i++){
            if(chosenWord[i] == letter){
                    marks[i] = chosenWord[i]
            }
      } 
     // i imagine this is where i put some sort of code to show that guessed letter?

     System.out.println("You guessed a letter!" + new String(marks));
}

我没有检查语法，但是你应该知道我在做什么

Answer 2

String类包含一个indexOf(String c)方法，该方法返回子字符串第一次出现的索引。例如，如果word是delicious，那么word.indexOf("i")将返回3，即子字符串"i"的第一个索引

但是子字符串"i"的所有其他出现情况又如何呢？嗯，indexOf方法很容易被覆盖以帮助实现这一点。它还有另一个版本，indexOf(String ch, int fromIndex)接受起始索引。继续我们前面的示例，如果您这次请求word.indexOf("i", 4)，您将返回5，即字符串"delicious"中子字符串"i"的第一个索引，如果我们在第四个索引之前贴现每个索引

这样想，indexOf有点像charAt的反面。charAt接受一个索引并为您提供一个字符，indexOf接受一个字符或字符串并为您提供其第一个索引

Answer 3

这是我做的。 我认为在这里使用数组要好得多

public static void main(String[] args) {
    String[] words = {"gluttony", "lust", "greed", "pride", "despair", "wrath", "vainglory", "rhythm", "delicious", "better", "jacuzzi", "ironman", "captainamerica", "thor", "hulk", "spiderman", "antman", "batman"}; //declares and initailise array of words to guess
    String word[] = (words[(int) (Math.random() * words.length)]).split(""); //chooses random word from the word array and creates a array of letters
    String[] marks = new String[word.length];
    Arrays.fill(marks,"-"); // creates and fills an array with dashes
    Scanner in  = new Scanner(System.in);
    String letter = "";
    int counter = 0;
    while(Arrays.toString(marks).contains("-")) {
        counter++;
        System.out.println("This is your word!: " + String.join("", marks));
        System.out.print("Guess a letter ");
        letter = String.valueOf(in.next(".").charAt(0));
        for (int i = 0; i < word.length; i++) {
            if(word[i].equals(letter)){
                marks[i] = word[i];
            }
        }
    }
    System.out.println("Congratulations your word is " + String.join("",marks) + "You did it in " + counter + "trials");
}

}

Answer 4

这里有一些代码让你开始。从用户那里获取整行内容，而不是使用next（），这一点很重要。。。除非您是一名经验丰富的程序员，并且了解next（）迭代输入的方式，否则我强烈建议您使用nextLine（），因为它更易于使用

        char letter = 0; //declares and initailise letter
        String [] words = { "gluttony", "lust", "greed", "pride", "despair", "wrath", "vainglory", "rhythm", "delicious", "better", "jacuzzi" , "ironman", "captainamerica", "thor", "hulk", "spiderman", "antman", "batman"}; //declares and initailise array of words to guess
        String word = words[(int) (Math.random() * words.length)]; //chooses random word from the word array
        String [] marks = new String[word.length()];
        for (int i=0;i<word.length(); i++) // for method for displaying the correct word as dashes
        {
            marks[i] = "-"; //dashes to represent the correct word.
        }

        HashSet<Character> lettersGuessed = new HashSet<>(); //keep track of letters guessed
        Scanner input = new Scanner(System.in);
        String userInput = "";
        String currentWord = "";

        while(true)
        {
            System.out.print("Word is - ");
            currentWord = "";
            for(int i = 0; i < marks.length; i++)
            {
                System.out.print(marks[i]);
            }

            System.out.print("\nGuess a letter - ");
            userInput = input.nextLine(); //always grab lines
            if(userInput.length() != 1)
            {
                System.out.println("Invalid guess - " + userInput);
            }
            else if(lettersGuessed.contains(userInput.charAt(0)))
            {
                System.out.println("You already guess that character - " + userInput);
            }
            else if(word.contains(userInput))
            {
                lettersGuessed.add(userInput.charAt(0));
                currentWord = "";
                for(int i = 0; i < word.length(); i++)
                {
                    if(word.charAt(i) == userInput.charAt(0))
                    {
                        marks[i] = "" + userInput.charAt(0);
                    }
                    currentWord += marks[i];
                }
            }

            if(currentWord.equals(word))
                break;
        }

        System.out.println("You guessed it! The word was " + word + "!");

输出

Word is - ----
Guess a letter - l
Word is - --l-
Guess a letter - h
Word is - h-l-
Guess a letter - l
You already guess that character - l
Word is - h-l-
Guess a letter - u
Word is - hul-
Guess a letter - tg
Invalid guess - tg
Word is - hul-
Guess a letter - k
You guessed it! The word was hulk!