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java当only equals被重写时,为什么列表会将项查找为true?

我知道hashcode和equals都需要重写。我尝试了下面的程序,想知道为什么列表能够搜索学生,而set不能搜索学生,因为只有equals被覆盖:

import java.util.*;

class Student {
private int id;
private String name;

public Student(int id, String name) {
    this.name = name;
    this.id = id;
}

public int getId() {
    return id;
}

public void setId(int id) {
    this.id = id;
}

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

@Override
public boolean equals(Object obj) {
    if (obj == null) return false;

    if (!(obj instanceof Student))
        return false;

    if (obj == this)
        return true;

    return this.getId() == ((Student) obj).getId();
}
}

public class StudentHashcodeEquals {
public static void main(String[] args) {
    Student alex1 = new Student(1, "Alex");
    Student alex2 = new Student(1, "Alex");

    System.out.println("alex1 hashcode = " + alex1.hashCode());
    System.out.println("alex2 hashcode = " + alex2.hashCode());
    System.out.println("Checking equality between alex1 and alex2 = " + alex1.equals(alex2));

    List<Student> studentsLst = new ArrayList <Student>();
    studentsLst.add(alex1);
    studentsLst.add(alex2);

    System.out.println("Arraylist size = " + studentsLst.size());
    System.out.println("Arraylist contains Alex = " + studentsLst.contains(new Student(1, "Alex")));

    HashSet <Student> students = new HashSet <Student>();
    students.add(alex1);
    students.add(alex2);

    System.out.println("HashSet size = " + students.size());
    System.out.println("HashSet contains Alex = " + students.contains(new Student(1, "Alex")));
}
}

/*
alex1 hashcode = 366712642
alex2 hashcode = 1829164700
Checking equality between alex1 and alex2 = true
Arraylist size = 2
Arraylist contains Alex = true
HashSet size = 2
HashSet contains Alex = false
*/

当student被插入列表时,我假设它会将它插入两个不同的bucket中,因为hashcode实现不是prsent,默认对象hashcode会被插入,它会将它们存储到两个不同的hash Code中,当搜索另一个对象时,它必须首先通过哈希代码定位bucket,但哈希代码实现不存在,然后列表如何仍然能够识别它,而set却不能

谢谢


共 (1) 个答案

  1. # 1 楼答案

    列表不使用对象的哈希代码。根据其类型,它们存储对对象的引用数组

    如果在列表中调用contains,它将使用.equals()在列表中迭代,以检查对象是否在列表中