当存在未知数量的空格时，使用java替代正向查找

Question

我的replacerRegex是

("schedulingCancelModal": \{\s*? "title": ")(.+?)(?=")

获取正确的值，即valueToBePicked：

但是，我如何使("schedulingCancelModal": \{\s*? "title": ")不被包括在结果中，就像正向查找一样

到目前为止，我的Java代码：

Pattern replacerPattern = Pattern.compile(replacerRegex);
Matcher matcher = replacerPattern.matcher(value);

while (matcher.find()) {
    String valueToBePicked = matcher.group();
}

Answer 1

您只需选择matcher.group(2)即可获得第二个捕获组的内容。例如：

    String replacerRegex = "(\"schedulingCancelModal\": \\{\\s*? \"title\": \")(.+?)(?=\")";
    String value = "\"valueToBePicked\": \"schedulingCancelModal\": {\n \"title\": \"Are you sure you want to leave scheduling?\", ... }";
    Pattern replacerPattern = Pattern.compile(replacerRegex);
    Matcher matcher = replacerPattern.matcher(value);

    while (matcher.find()) {
        String valueToBePicked = matcher.group(2);
        System.out.println(valueToBePicked);
    }        

输出：

Are you sure you want to leave scheduling?

Demo on rextester