java意图传递数据未成功

Question

我正在制作一个游戏的得分列表，我使用了下面的代码将scoretime传递给ScoreActivity，但我不知道为什么它只显示默认的数字“1”

long timeSpent = System.currentTimeMillis() - initialTime;
timeSpent = (long) (timeSpent / 1000.0);
int apple = (int)timeSpent;
Intent scoreIntent = new Intent(GameActivity.this,ScoreActivity.class);
scoreIntent.putExtra("score",apple);

AlertDialog alertDialog = new AlertDialog.Builder(GameActivity.this).create();
alertDialog.setTitle("Game Over!");
alertDialog.setMessage(" Total time " + String.valueOf(timeSpent));
alertDialog.setButton(AlertDialog.BUTTON_POSITIVE,"Exit", new DialogInterface.OnClickListener() {

    @Override
    public void onClick(DialogInterface dialog, int which) {

        Intent i =new Intent(getContext(), ScoreActivity.class);
        getContext().startActivity(i);
    }

在计分活动中

TextView myText;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_score);
    myText = (TextView)findViewById(R.id.text444);
    Intent scoreIntent = getIntent();
    int rating = scoreIntent.getIntExtra("score", 1);
    String str = Integer.toString(rating);
    myText.setText(rating);
}

Answer 1

你需要在这里传递你的价值

Intent i =new Intent(getContext(),   ScoreActivity.class);
 i.putExtra("score",Apple);
getContext().startActivity(i); 

Answer 2

它显示默认值，因为您创建了一个意图并在其中添加了额外内容

Intent scoreIntent = new Intent(GameActivity.this,ScoreActivity.class);
scoreIntent.putExtra("score",apple);

没错，但当你开始活动时，你使用了另一个意图

Intent i =new Intent(getContext(), ScoreActivity.class);
getContext().startActivity(i);

而且apple的值不在新的intent i中，因此解决方案是将您的intent scoreIntent设置为final，您可以通过onClick()方法访问它，如：

final Intent scoreIntent = new Intent(GameActivity.this,ScoreActivity.class);
scoreIntent.putExtra("score",apple);

从onClick()开始，你这样做

getContext().startActivity(scoreIntent );