c#将Java/Android连接到。网络服务

Question

我刚刚建立了一个新的平台。net默认Web服务和HelloWorld方法

现在，我正在尝试连接一个Java/Android简单实现。net网络服务。我被HttpTransportSE电话卡住了。它不起作用，实际上它就停在这里。没有错误

下面是代码示例：

private class SoapAccessTask extends AsyncTask<String, Void, String> {

  protected String doInBackground(String... urls){
     final String METHOD_NAME = "HelloWorld";
     final String NAMESPACE = "http://tempuri.org";
     final String SOAP_ACTION = "http://tempuri.org/HelloWorld;
     final String URL = "http://localhost:2986/Service1.asmx;

     SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
     SoapSerializationEnvelop envelop = new SoapSerializationEnvelop(SoapEnvelop.VER11);
     AndroidHttpTransport 安卓Http = new AndroidHttpTransport(URL);
     安卓Http.call(SOAP_ACTION, envelop);
  }
}

你知道为什么这样不行吗

问候

Answer 1

在代码中输入以下行：

envelope.dotNet = true;
envelope.setOutputSoapObject(request);

编辑：

1. dotNet标志必须为true才能生效。来自kSOAP2的NET web服务调用（当您使用.NET web服务时）。因此envelope.dotNet = true;

2. 最后，SoapObject实例“request”被指定为soap调用到信封的出站消息。因此envelope.setOutputSoapObject(request);

Answer 2

如果您正在使用ksoap2访问asmx web方法，那么这段代码可能会对您有所帮助

public class ServiceHandler {
    private static String SOAP_ACTION;    
    private static String OPERATION_NAME;    
    private static final String WSDL_TARGET_NAMESPACE = "http://xxx.example.com/";    
    private static final String SOAP_ADDRESS = "http://xxx.example.com/WebService.asmx";

    /**
     * call WebMethod
     * 
     * @param param1 
     * @param param2 
     * 
     * @return //sample code
     */
    public static String callWebMethod(String param1,String param2){

        OPERATION_NAME = "myFunc";
        SOAP_ACTION = "http://xxx.example.com/myFunc";

        SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME);

        request.addProperty("param1",param1);
        request.addProperty("param2",param2);

        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet = true;

        envelope.setOutputSoapObject(request);

        HttpTransportSE httpTransport = new HttpTransportSE(SOAP_ADDRESS);

        try{                  
            httpTransport.call(SOAP_ACTION, envelope);      
            SoapObject object = (SoapObject) envelope.getResponse();
            //get object
        }catch(Exception exception){
            System.out.println(exception.toString());
            return "";          
        }
    }

    return "";
}