java如何检索列表中具有特定属性的所有对象？

Question

例如，我从服务门户创建了一个“事件”列表：

List<Incident> incidentObjectList = new ArrayList<>();
for (int i = 0; i < incidentNumberList.size(); i++) {
    Incident incident = new Incident();
    incident.setIncidentNumber(incidentNumberList.get(i));
    incident.setSummary(summaryList.get(i));
    incident.setRequestId(requestIdList.get(i));
    incident.setPriority(priorityList.get(i));
    incident.setLastModifiedDate(lastModifiedDateList.get(i));
    incidentObjectList.add(incident);
}
System.out.println("Incident Object List" + incidentObjectList);

每个事件都有几个属性，但我只想从由优先级为Low的事件对象组成的原始列表创建一个新列表。在这种情况下，incident.getPriority()将为新列表中的所有对象返回字符串Low

String[] dataGreenArray = incidentObjectList.get();
retrieveTickets(dataGreenArray, listViewGreen);

Answer 1

在incidentObjectList上循环并检查每个元素的优先级

for (Incident incident: incidentObjectList)
{
    if (incident.getPriority().equals("Low")
        desiredList.add(incident);         // or whatever you want to do
}

这是一个非常基本的解决方案，但除非您专门寻找其他解决方案，否则它应该会起作用。希望有帮助

Answer 2

在Java8中

List<Incident> list = incidentObjectList.stream()
                                        .filter(e->e.getPriorty().equals("Low"))
                                        .collect(Collectors.toList());