java问题与循环转发

Question

所以我的循环有一个问题，我的目的是在进入下一行之前填满整个月，就像这样

     January   2000        February   2000        March   2000   
|S  M Tu  W Th  F  S| |S  M Tu  W Th  F  S| |S  M Tu  W Th  F  S|
                   1         1  2  3  4  5            1  2  3  4 
 2  3  4  5  6  7  8   6  7  8  9 10 11 12   5  6  7  8  9 10 11
 9 10 11 12 13 14 15  13 14 15 16 17 18 19  12 13 14 15 16 17 18
16 17 18 19 20 21 22  20 21 22 23 24 25 26  19 20 21 22 23 24 25
23 24 25 26 27 28 29  27                    26 27 28 29 30 31

但我的结果是这样的-

          January   2000        February   2000        March   2000   
|S  M Tu  W Th  F  S||S  M Tu  W Th  F  S||S  M Tu  W Th  F  S|
                   1        1  2  3  4  5           1  2  3  4 
     April   2000        May   2000        June   2000   
|S  M Tu  W Th  F  S||S  M Tu  W Th  F  S||S  M Tu  W Th  F  S|
                   1     1  2  3  4  5  6              1  2  3 
     July   2000        August   2000        September   2000   
|S  M Tu  W Th  F  S||S  M Tu  W Th  F  S||S  M Tu  W Th  F  S|
                   1        1  2  3  4  5                 1  2 
     October   2000        November   2000        December   2000   
|S  M Tu  W Th  F  S||S  M Tu  W Th  F  S||S  M Tu  W Th  F  S|
 1  2  3  4  5  6  7           1  2  3  4                 1  2 

可以做什么或添加什么来使其充分发挥作用并通过？我觉得我有一个循环的问题，但我真的不能确定它

public static int day(int month, int day, int year) {
        int y = year - (14 - month) / 12;
        int x = y + y / 4 - y / 100 + y / 400;
        int m = month + 12 * ((14 - month) / 12) - 2;
        int d = (day + x + (31 * m) / 12) % 7;
        return d;
    }

    public static boolean isLeapYear(int year) {
        if ((year % 4 == 0) && (year % 100 != 0))
            return true;
        if (year % 400 == 0)
            return true;
        return false;
    }    
public static void main(String[] args) {

    // take in command line argument to determine the month and year
    int month = 0;
    int year = 2000;    
    String[] months = { "", // left empty so that months[1] = "January"
                "January", "February", "March", "April", "May", "June", "July", "August", "September", "October",
                "November", "December" };

        // days[i] = number of days in month i
        int[] days = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };

        for (month = 1; month < 12;) {

            // check for leap year
            if (month == 2 && isLeapYear(year))
                days[month] = 29;

            // print calendar header
            for (int f = 0; f < 3; f++) {

                System.out.print("     " + months[month] + "   " + year + "   ");
                month++;
            }
            System.out.println();
            for (int f = 0; f < 3; f++) {
                System.out.print("|S  M Tu  W Th  F  S|");
            }
            System.out.println();

            // print the calendar
            month -= 3;
            for (int f = 0; f < 3; f++) {
                int d = day(month, 1, year);
                for (int i = 0; i < d; i++)
                    System.out.print("   ");
                for (int i = 1; i <= days[month]; i++) {

                    System.out.printf("%2d ", i);
                    if (((i + d) % 7 == 0) || (i == days[month])) {
                        if(month<12)
                        month++;
                        break;
                    }

                }

            }
            System.out.println();

        }

Answer 1

正如Perdi Estaquel所说，你又错过了一个循环

for (month = 1; month < 12;) {
}

每月只启用一次天输出，您需要这样做

for (month = 1; month < 12;) {
    // month and header output stay unchanged

    for (int calendarLine = 1; calenderLine <= 5; calenderLine++) {
        // your calender output here
    }
}

Answer 2

您缺少一个循环

外部循环从最左边的月份到最右边的月份（总共3个）。但这只会给你一句话

你必须用另一个能穿过所有线的环来包裹它

Answer 3

你的方法有点令人头痛。我并不是说它不起作用，但这样的嵌套循环太复杂了

您可以定义一个Month类，该类将有header()和getLine(int lineNumber)方法

您还可以有一个Quarter类，该类将有header()和getLine(int lineNumber)方法。它将包含三个月的对象

然后，您可以在Quarter对象中循环（一年4个）并打印标题，后跟6行