musicbrainz使用musicbrainzws2java定位各种曲目的mbid

Question

我已经将musicbrainzws2 java库导入到我的项目中，并且我一直在阅读MusicBrainz在其web服务上的文档。但这很令人困惑。我想知道是否有人能帮助我了解如何浏览MusicBrainz数据库。我不懂术语，我使用数据库的主要目的是收集各种歌曲的mbid

现在这就是我所拥有的

    public static void main(String[] args) {

    ArtistSearchFilterWs2 filter = new ArtistSearchFilterWs2();

    filter.setArtistName("Lindsey Stirling");
    filter.setLimit((long) 100);
    filter.setMinScore((long) 0);
    filter.setOffset((long) 0);

    ArtistSearchWs2 search = new ArtistSearchWs2(filter);

    List<ArtistResultWs2> result = search.getFullList();

    /*
    for(ArtistResultWs2 artist : result) {
        System.out.println(artist.getArtist().getName() + " " + i);
        i++;

        if(artist.getArtist().getName() == "Lindsey Stirling") {

            System.out.println(artist.getArtist().getName() + " " + i);
            break;
        }

    }
    */

    String artistName = result.get(0).getArtist().getName();
    System.out.println(artistName);

    List<ReleaseWs2> releases = result.get(0).getArtist().getReleaseList().getReleases();

    System.out.println(releases.size());

    for(ReleaseWs2 release : releases) {
        System.out.println(release.getTitle());

    }

出于某种原因，它说艺术家林赛·斯特林（Lindsey Stirling）有0个版本，除此之外，我不知道如何根据艺术家和专辑搜索特定歌曲

Answer 1

releases不包含任何元素，因为搜索服务器不会为艺术家搜索返回此信息。为了澄清这一点：MusicBrainz的“normal”web service和search web service在其输出中使用相同的XML模型，这意味着ArtistWs2类可以表示它们中任何一个的结果

除了搜索web服务之外，正常的web服务允许您request more information关于正在检索信息的实体（在本例中，您需要artist的发布信息，因此必须在inc参数中包含releases）

您可以查看搜索服务器为您的搜索返回的XMLhere，对包含发布信息的普通web服务的请求是here

以下代码（减去导入）将执行您想要的操作：

ArtistSearchFilterWs2 filter = new ArtistSearchFilterWs2();

filter.setArtistName("Lindsey Stirling");
filter.setLimit((long) 100);
filter.setMinScore((long) 0);
filter.setOffset((long) 0);

ArtistSearchWs2 search = new ArtistSearchWs2(filter);
List<ArtistResultWs2> result = search.getFullList();

String artistName = result.get(0).getArtist().getName();
System.out.println(artistName);

// This is the artist as returned by the search server.
ArtistWs2 artist = result.get(0).getArtist();

Artist controller = new Artist();
// This is where you tell the library that you want to have the artists
// releases included in the result.
controller.getIncludes().setReleases(true);

// This is the artist as returned by the MusicBrainz server, including the
// release information.
ArtistWs2 lindsey = controller.lookUp(artist);

List<ReleaseWs2> releases = lindsey.getReleaseList().getReleases();
System.out.println(releases.size());

for (ReleaseWs2 release : releases) {
    System.out.println(release.getTitle());
}

要了解搜索是如何工作的，您应该首先阅读the general documentation，然后在recording search documentation中找到所需的搜索字段。如果要在特定专辑中搜索特定艺术家的歌曲（recording，请使用artist和releases字段。例如，要通过“ShatterMe”上的“Lindsey Stirling”搜索“Mirror Haus”，您需要执行以下查询："Mirror Haus" AND artist:"Lindsey Stirling" AND release:"Shatter Me"

以下代码将执行此操作：

    RecordingSearchFilterWs2 recfilter = new RecordingSearchFilterWs2();
    recfilter.setLimit((long) 100);
    recfilter.setMinScore((long) 0);
    recfilter.setOffset((long) 0);
    recfilter.setQuery("\"Mirror Haus\" AND release:\"Shatter Me\" AND artist:\"Lindsey Stirling\"");
    RecordingSearchWs2 recsearch = new RecordingSearchWs2(recfilter);
    List<RecordingResultWs2> recresult = recsearch.getFullList();
    System.out.println(recresult.size());
    System.out.println(recresult.get(0).getRecording().toString());