如何创建一个for循环，以便在Java中按顺序打印字符串数组？

Question

我试图创建一个for循环，将以下所有字符串打印到下面的println语句中，但无法确定如何让for循环打印数组。我不断收到错误“找不到符号”将有一个扫描仪，允许用户在每个println语句后输入

 public static void Real() {
    String[] sequence;
    sequence = new String[4];
    sequence[0] = ("first");
    sequence[1] = ("second");
    sequence[2] = ("third");
    sequence[3] = ("fourth");
    int number;
    for (number = 0; number <= sequence(); number++ ) {
        System.out.println("Input your " + sequence + " lap time");
    }
}

Answer 1

代码中存在一些语法错误，而且java中的方法名称应该以小写开头

下面的代码应该可以完成这项工作

 public static void real() {
   String[] sequence;
   sequence = new String[4];
   sequence[0] = "first";
   sequence[1] = "second";
   sequence[2] = "third";
   sequence[3] = "fourth";
   int number;
   for (number = 0; number < sequence.length; number++ ) {
     System.out.println("Input your " + sequence[number] + " lap time");
   }
}

Answer 2

每个循环使用一次怎么样

for (String s : sequence)
            System.out.println("Input your " + s + " lap time");

Answer 3

用number<sequence.length代替number <= sequence()

及

在系统中使用sequence[number]而不是sequence。出来println（）

Answer 4

不能仅通过在print语句中引用数组的名称来打印数组，需要遍历所有元素并在每个索引处打印元素。您可以使用语法数组[index]访问元素

您需要从0循环到最后一个索引，我认为您试图从sequence（）得到的是数组的大小。要获得数组的大小，需要使用数组。长度

因此，您的代码应该如下所示：

public static void Real() { 
    String[] sequence; 
    sequence = new String[4];
    sequence[0] = ("first"); 
    sequence[1] = ("second"); 
    sequence[2] = ("third"); 
    sequence[3] = ("fourth"); 
    int number; 
    for (number = 0; number < sequence.length; number++) { 
        System.out.println("Input your " + sequence[number] + " lap time"); } }

Answer 5

public static void Real(String a[]) {
    String[] sequence;
    sequence = new String[4];
    Scanner input= new Scanner(System.in);

    sequence[0] = ("first");
    sequence[1] = ("second");
    sequence[2] = ("third");
    sequence[3] = ("fourth");
    int number;
    for (number = 0; number <4 ; number++ ) {
        System.out.println("Input your " + sequence[number] + " lap time");
        System.out.println("Input");
        variable = inupt.nextDatatype();
    }
}

这是我理解后的答案。 顺便说一下，我不知道这件事