java如何删除数组中的最后一个输入元素？
对于这个程序，我让一个用户使用private static void add()方法将元素输入到一个5空间数组中。添加这些元素后，用户就可以使用private static void delete()方法，该方法允许用户输入他们希望删除的数组中的数字。当输入要删除的数字时，除非我尝试删除数组的currentSize的最后一个数字，否则程序工作得非常好。例如，如果我有一个具有以下索引和值的数组：
0. = 1
1. = 2
2. = 3
3. = 4
4. = <empty>
数组的currentSize当前为4。如果我试图删除索引3中的值4，程序将不会删除值4。如果在尝试删除值4之后尝试删除值3、2或1，则这些值也不会删除。另一方面，如果我想先删除值4以下的任何值，即值1、2和3，程序将正常工作，直到我尝试删除索引0中的值4为止。如果此时尝试删除值4，则不会删除任何内容。如果我尝试添加一个值，比如1，在尝试删除值4之后，值4将替换为值1。如果我尝试删除索引0中的值4两次，然后尝试添加一个新值，则会得到一个IndexOutOfBoundsException: -1。我相信这与currentSize--递减有关，而在private static void delete()方法中存在的删除元素算法中，假定它不存在。如果有人对此有解决方案，我们将不胜感激，谢谢。该程序发布在下面。我已经评论了private static void delete()方法中给我带来问题的部分。这是我得到的堆栈跟踪：
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: -1
at ArrayManager.add(ArrayManager.java:35)
at ArrayManager.main(ArrayManager.java:216)
/**
* A class that contains methods to carry out the Add, Update, Delete, Drop, Resize, and End commands to alter the state of an array with 5 integers.
*/
public class ArrayManager
{
// Array of 5 integers to be modified
private static int [] values = new int [5];
private static int currentSize = 0;
private static int position = 0;
//private static int index = 0;
static Scanner in = new Scanner(System.in);
/**
* A method that inserts an entered value into the array as long as it is between 1 and 99. If the array is full, an error message will be printed explaining that the array is full.
*/
private static void add()
{
System.out.println("Enter values between 1 and 99, inclusive that you would like to add to the array.");
if(in.hasNextInt())
{
int n = in.nextInt();
if(n >= 1 && n <= 99)
{
if(currentSize < values.length)
{
values[currentSize] = n;
currentSize++;
}
else
{
System.out.println("ERROR: The array is currently full.");
}
}
else
{
System.out.println("ERROR: The number entered must be between 1 and 99, inclusive.");
}
}
else
{
System.out.println("ERROR: String has been entered. Enter an Integer.");
}
}
/**
* A method that asks the user to enter a value they wish to delete in the array. The following values are then shifted down in index in the array. If the value chosen does not exist in the array, an error message is displayed explaining that the value entered does not exist in the array.
*/
private static void delete()
{
int n = 0;
System.out.println("Please enter the value in the array that you wish to remove.");
if(in.hasNextInt())
{
n = in.nextInt();
for(position = 0; position < values.length; position++)
{
if(values[position] == n)
{
// The stack trace points me back to this section of code which removes the specified value in the values array.
for(int i = position + 1; i < currentSize; i++)
{
values[i - 1] = values[i];
values[i] = 0;
}
currentSize--;
break;
}
else if(position == values.length - 1)
{
System.out.println("ERROR: The value entered does not exist in the array.");
}
}
}
else
{
System.out.println("ERROR: String has been entered. Enter an Integer.");
}
}
/**
* A method that prints out the modified array.
*/
public static void printArray()
{
System.out.println("* Current Array Contents *");
for(int i = 0; i < values.length; i++)
{
if(values[i] != 0)
{
System.out.println(i + ". = " + values[i]);
}
else if(values[i] == 0)
{
System.out.println(i + ". = <empty>");
}
}
}
# 1 楼答案
位置是值数组最后一个元素的索引的角点情况处理不正确。在这种情况下，代码开始迭代下一个索引中的元素，以便将所有元素移动1个位置，而for循环中的条件不满足该条件
for(int i = position + 1; i < currentSize; i++)解决方案是检查该条件并显式处理它