通过索引“Java”彼此相等的两个数组

Question

如果用户在运行此程序后键入自己的姓名，则程序应输出

Hello Sully you are Manager !

但实际情况是，程序将打印Sully是管理者，并将继续将Sully与数组中的其他值进行比较。我只是在用java学习数组

    public class Aconstructors {

        public static void main(String[] args) {
            Scanner scan = new Scanner(System.in) ;
            String user ;
            String [] empName , empPos ;
            empName = new String [2] ;
            empName [0] = "Sully" ;
            empName [1] = "John" ;
            empPos = new String [2] ;
            empPos [0] = "Manager" ;
            empPos [1] = "Employ" ;

            System.out.println("Enter Your Name to know Your Position : ");
            user = scan.nextLine()  ;

            for (int i = 0 ; i <empName.length;i++ ) {
                //check if user input is equals
                if (empName[i].equals(user)) {
                    // indexes are equals
                    empName.equals(empPos.length );
                    System.out.printf("Hello %s you are %s !!\n",empName[i],empPos[i]);
                    // if user input is not equal
                }
                else if   (!empName[i].equals(user))  {
                    System.out.println("unknowing user !! ");
                }
            }
        }
    }

John的输出：

Enter Your Name to know Your Position : 
John
unknowing user !! << as you see here java checking the values 
Hello John you are the Employ  !! << java found John 

Sully的输出：

Enter Your Name to know Your Position : 
Sully
Hello Sully you are Manager !! << found Sully 
unknowing user !! << didnt stop  

Answer 1

在循环之前声明一个布尔变量unknown=true;，以检查列表中是否存在该名称。如果在列表中找到该名称，请更改unknown=false;
循环完成后，如果变量未更改，即名称不在列表中，则打印消息“未知”

Scanner scan = new Scanner(System.in) ;
String user ;
String [] empName , empPos ;
empName = new String [2] ;
empName [0] = "Sully" ;
empName [1] = "John" ;
empPos = new String [2] ;
empPos [0] = "Manager" ;
empPos [1] = "Employ" ;

System.out.println("Enter Your Name to know Your Position : ");
user = scan.nextLine()  ;

boolean unknown = true;

for (int i = 0 ; i <empName.length;i++ ) {
    //check if user input is equals
    if (empName[i].equals(user)) {
        unknown = false;
        System.out.printf("Hello %s you are %s !!\n",empName[i], empPos[i]);
        break;
    }
}

if (unknown)
    System.out.println("unknowing user !! ");

Answer 2

尝试改进您的for-loop-like

for (int i = 0 ; i <empName.length;i++ ) {
            //check if user input is equals
            if (empName[i].equals(user)) {
                // indexes are equals 
                System.out.printf("Hello "+empName[i]+" you are "+empPos[i]);
                break;
                // if user input is not equal
            } else if   (!empName[i].equals(user))  {
                System.out.println("unknowing user !! ");
            }
        }

您只需要将您的用户输入与empName数组进行比较，并打印该员工的位置，这非常简单，因为您的索引对于这两者都是相同的，如果找到匹配项，则使用break来中断循环