java基于每个字母的ASCII值的句子中的平均单词值

Question

我想根据ASCII值计算每个单词的平均值 例如：你好，H=72，e=101，l=108，l=108，o=111
将其相加，得到500，然后根据字母数计算平均值，即500/5=100，因此Hello的平均值=100，与“World”等的计算方法相同。 最后计算所有单词的平均值，将其相加并显示为整个句子的最终平均值 这是我创建的代码，但它在线程“main”java中给出了一个异常。lang.ArrayIndexOutOfBoundsException

   import java.util.*;
   import java.lang.*;
   import java.io.*;
    class Word
    {
    public static void main (String[] args) 
    {

    String str="Hello World";
    int average1=0;
    int j=0;
    int[] average=new int[20];
    String[] s=str.split(" "); //Splitting into each word
    for(String s1 : s)
    {
    char[] c=s1.toCharArray();
    for(int i=0;i<str.length();i++)
    {
        average[i]=(int)c[i]; //Average ASCII based value for each word
    }
    while(average[j]!=0)
    {
    average1=average[j]/s1.length(); //Sum up average of each Word and average of who words is calculated 
    System.out.print(average1); 
    j++;
    }
    }
    }
    }

如果有人能帮我一个好的逻辑，我将不胜感激

Answer 1

检查此代码。这比你的要简单一点。它对每个单词进行平均，然后对平均值进行平均

import java.util.*;
import java.lang.*;
import java.io.*;
class Word
{
    public static void main (String[] args)
    {

        String str="Hello World";

        String[] s = str.split(" ");
        int[] average = new int[s.length];
        for(int i = 0; i<s.length; i++) {
                int wordAverage = 0;
                System.out.println(s[i]);
                for(int j=0;j<s[i].length(); j++) {
                        wordAverage += (int)s[i].charAt(j); //Average ASCII based value for each word
                }
                average[i] = wordAverage/s[i].length();
                System.out.println(average[i]);
        }
        int finalAverage = 0;
        for(int i = 0; i<average.length; i++)
                finalAverage += average[i];
        finalAverage/=average.length;
        System.out.println(finalAverage);
    }
}

Answer 2

实现这一目标的简单方法是这样做：

public class WordAverage{
   public static void main (String[] args) {

       String str="Hello World"; 
       double average=0; // you need only one double variable, why double -> because of the division later 
        // note that if you don't want the decimal you can change it to int
        for(char c : str.toCharArray()){ // cycle through every char in the String
            if(c!=' '){ // if it is not a space
               average += (int)c; // sum its value
            }
        }

       average /= str.replace(" ", "").length(); // then divide the average value by the String length after removing the spaces (if any)
        System.out.println(average);
    }
  }

测试

Hello World     -> 102.0
How Are You?    -> 96.2
Fine Thank You! -> 95.23