具有文件名的java Spring批处理作业参数
我想用SpringBatch rest控制器和动态输入文件名创建项目
我的代码:Rest控制器
@RestController
公共类FileNameController{
@Autowired
JobLauncher jobLauncher;
@Autowired
Job job;
@RequestMapping("/launchjob")
public String handle(@RequestParam("fileName") String fileName) throws Exception {
Logger logger = LoggerFactory.getLogger(this.getClass());
try {
JobParameters jobParameters = new JobParametersBuilder()
.addString("input.file.name", fileName)
.addLong("time", System.currentTimeMillis())
.toJobParameters();
jobLauncher.run(job, jobParameters);
} catch (Exception e) {
logger.info(e.getMessage());
}
return "Done";
}
}
作业配置:
@Configuration
@EnableBatchProcessing 公共类JobConfig{
@Autowired
public JobBuilderFactory jobBuilderFactory;
@Autowired
public StepBuilderFactory stepBuilderFactory;
Filetasklet ft=new Filetasklet();
Logger log = LoggerFactory.getLogger(this.getClass().getName());
private String pathFile = urlCoffreFort + "\\" + ft.getFileName();
// => Configuration of Job
@Bean
public Job job() throws IOException {
return jobBuilderFactory.get("job")
.incrementer(new RunIdIncrementer())
.flow(step1())
.end()
.build();
}
//###### Steps
// => Step cecStep1
@Bean
public Step step1() throws IOException {
return stepBuilderFactory.get("fileDecrypt")
.<Person, String>chunk(100)
.reader(reader1())
.processor(processor1FileDecrypt())
.writer(writer1())
.faultTolerant()
.skip(Exception.class)
.skipLimit(100)
.build();
}
// ####### readers
// => reader1()
@Bean
public FlatFileItemReader<Person> reader1() throws IOException{
return new FlatFileItemReaderBuilder<CSCivique>().name("personItemReader")
.resource(new ClassPathResource(pathFile))
.delimited()
.delimiter(";")
.names(new String[] { "id", "nomNaissance", "prenom" })
.targetType(CSCivique.class)
.build();
}
// ######Processors
@Bean
public PersonItemProcessor1FileDecrypt processor1FileDecrypt() {
return new PersonItemProcessor1FileDecrypt();
}
// ######Writers
@Bean
public FlatFileItemWriter<String> writer1() {
return new FlatFileItemWriterBuilder<String>().name("greetingItemWriter")
.resource(new FileSystemResource("sav/greetings.csv"))
.lineAggregator(new PassThroughLineAggregator<>()).build();
}
}
当我编写url时: http://localhost:8080/launchjob?fileName=djecc5cpt.csv 控制台打印:
PreparedStatementCallback;错误的SQL语法[从批处理作业实例中选择作业实例ID、作业名称,其中作业名称=?和作业密钥=?];嵌套的异常是org。postgresql。util。PSQLException:错误:“批处理作业实例”关系不存在 职位:39
# 1 楼答案
SpringBatch不会决定在生产数据库中代表您创建表您需要事先做出决定并手动完成。否则,如果您使用SpringBoot,您可以通过设置
spring.batch.initialize-schema=always
来告诉SpringBoot为您的应用程序执行此操作有关类似的问题/答案,请参见https://stackoverflow.com/a/51891852/5019386