如何让java等待事件？

Question

我正在写一个简单的Tictatcoe游戏，每个玩家可以是人类也可以是人工智能。 所以，为了创建一个新的游戏实例，我做了如下工作：

Player p1=new RLPlayer(world);
gameInstance = new GameInstance(this, p1, new HumanPlayer(this, world), world);

然而，如果我做了类似的事情

Player p1=new RLPlayer(world);
gameInstance = new GameInstance(this, p1, new HumanPlayer(this, world), world);
Player p2=new RLPlayer(world);
gameInstance = new GameInstance(this, p2, new HumanPlayer(this, world), world);

只玩一场游戏。我发现这是因为对于HumanPlayer来说，它在等待移动输入时会停止并且什么也不做，如果之后有代码，它就会跳过。如何使执行等待输入？还是我的方法完全错了？我有一种感觉

public class HumanPlayer implements Player {
    private GameGUI gameGUI;
    private TicTacToeWorld world;

    public HumanPlayer(GameGUI gameGUI, TicTacToeWorld world){
        this.gameGUI = gameGUI;
        this.world = world;
    }

    public boolean makeMove() {
        gameGUI.setMoveInputEnabled(true);
        return false;
    }

    public boolean makeMove(int move){ //false means no move made
        if(!world.isMoveLegal(move)) return false;

        world.makeMove(move);
        gameGUI.setMoveInputEnabled(false);
        return true;
    }

    public void observeMove(){
    }

}

只是为了一些背景。我认为问题出在上面的那一个

public class GameInstance {
    private Player[] players;
    private TicTacToeWorld world;
    private GameGUI gameGUI;


    public GameInstance(GameGUI gameGUI, Player player1, Player player2, TicTacToeWorld world){
        this.gameGUI = gameGUI;
        players = new Player[]{player1,player2};
        this.world = world;

        runGame();
    }

    public void runGame(){
        gameGUI.updateGUI(world.getWorldState());
        while(!world.isGameOver()){
            if(!makePlayerMove())return;
            gameGUI.updateGUI(world.getWorldState());
        }
    }

    public boolean makePlayerMove(){
        int[] state;
        state = world.getWorldState();

        if(players[(state[0]-1)%2].makeMove()){
            players[state[0]%2].observeMove();
            return true;
        }
        else
            return false;
    }

    public void makePlayerMove(int move){ //force move AI OR input human move
        int[] state;
        state = world.getWorldState();

        if( players[(state[0]-1)%2].makeMove(move) ){ //if move was made e.g. AI. Human player would return false;
            gameGUI.updateGUI(world.getWorldState());
            players[state[0]%2].observeMove();
            runGame();
        }
    }
}

Answer 1

希望您不久前就明白了这一点，但为了完整起见：

游戏必须在GUI上运行事件。具体来说，在ActionLister的actionPerformed方法的实现中，必须运行AI移动代码，以响应人类玩家移动的点击。您需要从GUI按钮和事物的角度来思考，而不是从游戏流程的角度来思考。或者更确切地说，您必须根据GUI事件重新创建适当的游戏流程